Answer:
strength = 10⁻²/10⁻³ = 10 times more acidic
Explanation:
1. A solution with a pH of 9 has a pOH of
pH + pOH = 14 => pOH = 14 - pH = 14 - 9 = 5
2. Which is more acidic, a solution with a pH of 6 or a pH of 4?
pH of 4 => Higher [H⁺] = 10⁻⁴M vs pH of 6 => [H⁺] = 10⁻⁶M
3. How many times more acidic is a solution with a pH of 2 than a solution with a pH of 3?
soln with pH = 2 => [H⁺] = 10⁻²M
soln with pH = 3 => [H⁺] = 10⁻³M
strength = 10⁻²/10⁻³ = 10 times more acidic
4. What is the hydrogen ion concentration [H + ] in a solution that has a pH of 8?
[H⁺] = 10^-pH = 10⁻⁸M
5. A solution has a pOH of 9.6. What is the pH? (Use the formula.)
pH + pOH = 14 => pH = 14 - 9.6 = 4.4
Answer:
It is given in the question that molarity of the sulphuric acid is 2M, the volume of the sulphuric acid is 20 mL, the volume of the solution is 1`L.
Answer:
in disodium phosphate = 4 oxygen atoms
in phosphoric acid = 1 oxygen atom
Answer:
a. 7.8*10¹⁴ He⁺⁺ nuclei/s
b. 4000s
c. 7.7*10⁸s
Explanation:
I = 0.250mA = 2.5 * 10⁻³A
Q = 1.0C
1 e- contains 1.60 * 10⁻¹⁹C
But He⁺⁺ Carrie's 2 charge = 2 * 1.60*10⁻¹⁹C = 3.20*10⁻¹⁹C
(A).
No. Of charge per second = current passing through / charge
1 He⁺⁺ = 2.50 * 10⁻⁴ / 3.2*10⁻¹⁹C
1 He⁺⁺ = 7.8 * 10¹⁴ He⁺⁺ nuclei
(B).
I = Q / t
From this equation, we can determine the time it takes to transfer 1.0C
I = 1.0 / 2.5*10⁻⁴ = 4000s
(C).
Time it takes for 1 mol of He⁺⁺ to strike the target =?
Using Avogadro's ratio,
1.0 mole of He = (6.02 * 10²³ ions/mol ) * (1 / 7.81*10¹⁴ He ions)
Note : ions cancel out leaving the value of the answer in mols.
1.0 mol of He = 7.7 * 10⁸s
Gay-Lussac's law gives the relationship between pressure and temperature of a gas.
it states that for a fixed amount of gas of constant volume pressure is directly proportional to temperature.
P/T = k
where P - pressure, T - temperature and k - constant

where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation.
temperature should be in the kelvin scale,
T1 = 22 °C + 273 = 295 K
substituting the values in the equation

T = 492 K
new temperature - 492 - 273 = 219 °C