<h3>Answer:</h3>
<u>Easy</u><u>!</u><u>!</u>
2+<u>1</u><u>7</u>=19
#<em>h</em><em>o</em><em>p</em><em>e</em><em> </em><em>that</em><em> </em><em>helps</em>
Answer:
Esto se debe a que la heladera tiene mucha menor temperatura que la temperatura ambiente.
Esta menor temperatura ayuda a luchar contra los microorganismos que están en los alimentos (bacterias, hongos, etc) pues detiene en gran medida su repreduccion, la cual se ve maximizada en los rangos entre 5°C y 60°C, tal que la temperatura ambiente suele estar en el rango donde los microorganismos prosperan y se reproducen, es por ello que los alimentos se conservan mucho mejor en ambientes fríos (como la nevera) que en temperatura ambiente.
Answer:
c. Hfus is always negative.
Explanation:
Because energy is released when fusing solids
Answer:
Empirical formula: BH3
Molecular Formula: B2H6
Explanation:
To solve the exercise, we need to know how many boron atoms and how many hydrogen atoms the compound has. We know that of the total weight of the compound, 78.14% correspond to boron and 21.86% to hydrogen. As the weight of the compound is between 27 g and 28 g, using the above percentages we can solve that the compound has between 21.1 g and 21.8 g of boron, and between 5.9 g and 6.1 g of hydrogen:
100% _____ 27 g
78.14% _____ x = 78.14% * 27g / 100% = 21.1 g boron
100% ______27 g
21.86% ______ x = 21.86% * 27g / 100% = 5.9 g hydrogen
100% _____ 28 g
78.14% _____ x = 78.14% * 28g / 100% = 21.8 g boron
100% _____ 28g
21.86% _____ x = 21.86% * 28g / 100% = 6.1 g hydrogen
So, if the atomic weight of boron is 10.8 g, there must be two boron atoms in the compound that sum 21.6 g. The weight of hydrogen is 1 g, so the compound must have six hydrogen atoms.
The molecular formula represents the real amount of atoms that form a compound. Therefore, the molecular formula of the compound is B2H6.
The empirical formula is the minimum expression that represents the proportion of atoms in a compound. For example, ethane has 2 carbon atoms and 6 hydrogen atoms, so its molecular formula is C2H6, however, its empirical formula is CH3. Therefore, the empirical formula of the boron compound is BH3.
