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12345 [234]
3 years ago
10

What is the frequency of a 6.14 x 10^4 m wave

Chemistry
1 answer:
andrew11 [14]3 years ago
7 0
From the information give, I'm going to assume the wave is in a vacuum...

You use the equation: f= \frac{C}{Wavelength} where c is the constant for speed of light (3.00 x 10^{8}

so f= \frac{3.00x10^{8}}{6.14x10^{4}}

f= 4.89 x 10^{3} Hz (approximately)
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When a warm air mass is caught between two cooler air masses and the thicker cold air masses move underneath the thinner warm ai
almond37 [142]
An occluded front forms when a warm air mass is caught between two cooler air masses. The warm air mass is cut ofl or occluded' from the ground. The occluded warm front may cause clouds and precipitation. A swirling center of low air pressure is called a cyclone.
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3 years ago
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When a 1.00 L sample of water from the surface of the Dead Sea (which is more than 400 meters below sea level and much saltier t
Harlamova29_29 [7]

Answer: Molarity of MgCl_2 in the original sample was 1.96M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{\text{no of moles}}{\text{Volume in L}}

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{186g}{95g/mol}=1.96

Now put all the given values in the formula of molarity, we get

Molarity=\frac{1.96}{1.00L}

Molarity=1.96mol/L

Thus molarity of MgCl_2 in the original sample was 1.96M

4 0
3 years ago
explain the relationship between the rate of effusion of a gas and its molar mass. methane gas (ch4) effuses 3.4 times faster th
Musya8 [376]

The molar mass of the unknown gas is 184.96 g/mol

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

<h3>How to determine the molar mass of the unknown gas </h3>

The following data were obtained from the question:

  • Rate of unknown gas (R₁) = R
  • Rate of CH₄ (R₂) = 3.4R
  • Molar mass of CH₄ (M₂) = 16 g/mol
  • Molar mass of unknown gas (M₁) =?

The molar mass of the unknown gas can be obtained as follow:

R₁/R₂ = √(M₂/M₁)

R / 3.4R = √(16 / M₁)

1 / 3.4 = √(16 / M₁)

Square both side

(1 / 3.4)² = 16 / M₁

Cross multiply

(1 / 3.4)² × M₁ = 16

Divide both side by (1 / 3.4)²

M₁ = 16 / (1 / 3.4)²

M₁ = 184.96 g/mol

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

#SPJ1

3 0
2 years ago
Samples with masses of 5.5 g 2.27 g and 0.8995 g are mixed together. The sum of the masses of the three
Nadusha1986 [10]

Answer:

m=8.7g

Explanation:

Hello,

In this case, it is widely known that when measurements with different significant figures are put under mathematical operations, the final result must be displayed with the same amount of significant figures of the shortest measurement, thus, due to the fact that 5.5 g has two significant figures only the result is consequently shown with two significant figures as well as shown down below:

m=5.5g+2.27g+0.8995g\\\\m=8.6695g

By rounding the first six to seven due to the fact that the next six is greater than five, according to rounding rules, the result is:

m=8.7g

Best regards.

3 0
3 years ago
Layers of rock that bend can produce a downward fold known as a(n)
Schach [20]
Layers of rock that bend can produce a downward fold known as a syncline. 

This is the type of fold that occurs with the younger layers of rocks remaining closer to the center of the structure. Synclines can be recognized by the fact that the youngest layers of rocks always remain near the folds center.  

Hope this helped..
8 0
3 years ago
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