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Alik [6]
4 years ago
7

When I2 and FeCl2 are mixed together, iodine (I) cannot replace chlorine (Cl) in the compound because iodine is lower on the per

iodic table.
True
False
Chemistry
1 answer:
Nata [24]4 years ago
3 0

Answer: The given statement is true.

Explanation: If this reaction would have occurred, then this reaction would be considered as displacement reaction.

Displacement reactions are the reaction in which more reactive element displaces the less reactive element in a chemical reaction. This is based on the reactivity of elements.

Reactivity of elements is the tendency of the elements to gain or loose electrons. The reactivity decreases down the group in a periodic table.

In the given reaction, Iodine and chlorine are the elements of the same group in the periodic table and iodine lies below chlorine in the group. So, the reactivity of iodine is less than the reactivity of chlorine.

Hence, in the given reaction, iodine will not replace chlorine because it lies below in the periodic table.

FeCl_2+I_2\rightarrow \text{No reaction}

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Answer:

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Explanation:

Step 1:

Data obtained from the question. This include the following:

Molarity of base, KOH (Mb) = 0.850 M

Volume of base, KOH (Vb) = 38.34 mL

Volume of acid, H3A (Va) = 15.00 mL

Molarity of acid, H3A (Ma) =...?

Step 2:

The balanced equation for the reaction. This is given below:

H3A + 3KOH —> K3A + 3H2O

From the balanced equation above,

The mole ratio of the acid, H3A (nA) = 1

The mole ratio of the base, KOH (nB) = 3

Step 3:

Determination of the concentration of the acid, H3A.

The concentration of the acid, H3A can be obtained as follow:

MaVa / MbVb = nA/nB

Ma x 15 / 0.850 x 38.34 = 1/3

Cross multiply

Ma x 15 x 3 = 0.850 x 38.34

Divide both side by 15 x 3

Ma = (0.850 x 38.34) / (15 x 3)

Ma = 0.7242 M

Therefore, the concentration of acid, H3A is 0.7242 M

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