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Alik [6]
3 years ago
7

When I2 and FeCl2 are mixed together, iodine (I) cannot replace chlorine (Cl) in the compound because iodine is lower on the per

iodic table.
True
False
Chemistry
1 answer:
Nata [24]3 years ago
3 0

Answer: The given statement is true.

Explanation: If this reaction would have occurred, then this reaction would be considered as displacement reaction.

Displacement reactions are the reaction in which more reactive element displaces the less reactive element in a chemical reaction. This is based on the reactivity of elements.

Reactivity of elements is the tendency of the elements to gain or loose electrons. The reactivity decreases down the group in a periodic table.

In the given reaction, Iodine and chlorine are the elements of the same group in the periodic table and iodine lies below chlorine in the group. So, the reactivity of iodine is less than the reactivity of chlorine.

Hence, in the given reaction, iodine will not replace chlorine because it lies below in the periodic table.

FeCl_2+I_2\rightarrow \text{No reaction}

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A sample of no2 occupies 16,500 ml at stp. How many no2 molecules are in the sample?.
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2 years ago
2. Answer the following questions about a sample of calcium phosphate:
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Answer:

a) <u>310.18 g/mol</u>

<u>b) 4.352 moles Ca3(PO4)2</u>

<u>c) 2.6 * 10^24 molecules</u>

<u>d) 5.24 * 10^24 P atoms</u>

<u>e)13.056 moles Ca</u>

<u>f)</u>10825.3 grams

Explanation:

Step 1: Data given

Atomic mass of Ca = 40.08 g/mol

Atomic mass of P = 30.97 g/mol

Atomic mass of O = 16.0 g/mol

Step 2: Calculate molecular weight of Ca3(PO4)2

Molecular weight of Ca3(PO4)2 = 3*atomic mass of Ca + 2* atomic mass of P and 8* atomic mass of O

Molecular weight of Ca3(PO4)2 = 3*40.08 + 2*30.97 + 8*16.0  =<u> 310.18 g/mol</u>

Step 3: Calculate moles of Ca3(PO4)2 in 1350 grams

Moles Ca3(PO4)2 = mass Ca3(PO4)2 /molar mass

Moles Ca3(PO4)2 = 1350 grams / 310.18 g/mol

Moles Ca3(PO4)2 = <u>4.352 moles</u>

Step 4: Calculate molecules in 1350 grams

Molecules = moles * number of Avogadro

Molecules = 4.352 moles * 6.02 * 10^23

Molecules = <u>2.6 *10^24 molecules</u>

<u />

Step 5: Calculate moles Phosphorus

For 1 mol Ca3(PO4)2 we need 2 moles P

For 4.352 moles Ca3(PO4)2 we have 2*4.352 = 8.704 moles

Step 6: Calculate P atoms

Atoms P = 8.704 moles * 6.02*10^23

Atoms P =<u> 5.24 * 10^24 P atoms</u>

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Step 7: Calculate moles Calcium in 1350 grams

For 1 mol Ca3(PO4)2 we have 3 moles Ca

For 4.352 moles we have 3*4.352 = <u>13.056 moles Ca</u>

<u />

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<u>Step 8:</u> Calculate mass of 2.1 * 10^25 molecules of Ca3(PO4)2

Moles Ca3(PO4)2 = 2.1 * 10^25 / 6.02 * 10^23

Moles Ca3(PO4)2 = 34.9 moles

Mass Ca3(PO4)2 = 34.9 moles * 310.18 g/mol

Mass Ca3(PO4)2 = 10825.3 grams

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The answer is a) by increasing the temperature of the reactants.
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