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Ainat [17]
3 years ago
12

Steve is driving 590 miles to visit the Grand Canyon. He drives at an average rate of 59 miles per hour.

Mathematics
2 answers:
34kurt3 years ago
6 0

Answer:

its 10

Step-by-step explanation:

nlexa [21]3 years ago
4 0

Answer:

10 hr

Step-by-step explanation:

my answer needs to be atleast 20 words long so..........590÷59=10

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There were some people on a train 18 people get off at the first stop and 21 people get on the train there are now 65 people on
MissTica

Answer:

62

Step-by-step explanation:

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3 years ago
HELP PLZ!!!! How did you do 2a-5b? And what are the answers
Xelga [282]

both of the questions?

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3 years ago
the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​
madam [21]

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

f(t)=a(r)^t

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}

One year has 365 days.

Therefore, the amount remaining after one year will be:

\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

f(t)=Ce^{kt}

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

255=510e^{38k}

Solving for k:

\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)

Thus, our function is:

f(t)=510e^{t\ln(.5)/38}

Then after one year or 365 days, the amount remaining will be about:

f(365)=510e^{365\ln(.5)/38}\approx 0.6548

5 0
2 years ago
150 students attended the event they were 60 cars in the student parking lot what was the ratio of students to cars?
tatyana61 [14]
150 to 60. But the more commen why to do that were to simplify it.
6 0
3 years ago
Read 2 more answers
Find the slope of the line that passes through (1, 8) and (6, 1).
Alex777 [14]

Answer:

-7/5

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(1-8)/(6-1)

m=-7/5

3 0
2 years ago
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