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Zepler [3.9K]
3 years ago
15

Which three applications use technologies that apply the Doppler effect?

Physics
1 answer:
ivolga24 [154]3 years ago
8 0

Answer:

A, B & C are correct.

Explanation:

In physics, Doppler effect is a term used to describe the change in frequency of a wave during the relative motion existing between the source of the wave the person acting a the observer.

Looking at the options given, this Doppler effect is applicable to: air traffic control where traffic controllers attempt to direct the traffic on the ground; weather forecasting where the conditions of the atmosphere at a particular time and place is being predicted; and in building inspection where we can use a non destructive test equipment known as Schmidt hammer to career out min destructive tests on a building.

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During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 4.02 s, how high above the point where i
alukav5142 [94]

Answer:

d = 19.796m

Explanation:

Since the ball is in the air for 4.02 seconds, the ball should reach the maximum point from the ground in half the total time, therefore, t=2.01s to reach maximum height. At the maximum height, the velocity in the y-direction is 0.

So we know t=2.01, vi=0, g=a=9.8m/s and we are solving for d.

Next, you look for a kinematic equation that has these parameters and the one you should choose is:

d=vt+\frac{1}{2}at^2

Now by substituting values in, we get

d=(0\frac{m}{s})*(2.01s)+\frac{1}{2}(9.8\frac{m}{s^2})(2.01)^2

d = 19.796m

7 0
3 years ago
In 1666 at the age of 23, what scientist
scoray [572]

Answer:

<h3>B - Isaac Newton</h3>

Explanation:

He first thought of his system of gravitation which he hit upon by observing an apple fall from a tree,

The incident occurring in the late summer of 1666.

3 0
3 years ago
A player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory
____ [38]

At the highest point in its trajectory, the ball's acceleration is zero but its velocity is not zero.

<h3>What's the velocity of the ball at the highest point of the trajectory?</h3>
  • At the highest point, the ball doesn't go more high. So its vertical velocity is zero.
  • However, the ball moves horizontal, so its horizontal component of velocity is non - zero i.e. u×cosθ.
  • u= initial velocity, θ= angle of projection

<h3>What's the acceleration of the ball at the highest point of projectile?</h3>
  • During the whole projectile motion, the earth exerts the gravitational force with a acceleration of gravity along vertical direction.
  • But as there's no acceleration along vertical direction, so the acceleration along vertical direction is zero.

Thus, we can conclude that the acceleration is zero and velocity is non-zero at the highest point projectile motion.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory

A- neither the ball's velocity nor its acceleration are zero.

B- the ball's acceleration points upward.

C- the ball's acceleration is zero but its velocity is not zero.

D- the ball's velocity points downward.

Learn more about the projectile motion here:

brainly.com/question/24216590

#SPJ1

7 0
2 years ago
What kind of image is formed by an object that is placed beyond the center of curvature on the principal axis of a concave mirro
aev [14]

Answer:D.

Real, inverted, smaller than the object, and closer to the mirror than the object

Explanation: Real images will be inverted. As it is beyond the centre of curvature it is also beyond 2F which means that the image is inside the centre of curvature ( between F and 2F from the mirror ) As the image is closer to the mirror than the object it must be diminished in size

7 0
3 years ago
Water is a great conductor of electricity. True or False
astraxan [27]

Answer:

False

Explanation:

Think about every warning on electrical products, which is 'DO NOT KEEP NEAR WATER'

4 0
3 years ago
Read 2 more answers
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