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3 years ago

Which three applications use technologies that apply the Doppler effect?

Physics

1 answer:

ivolga24 [154]3 years ago

8 0

Answer:

A, B & C are correct.

Explanation:

In physics, Doppler effect is a term used to describe the change in frequency of a wave during the relative motion existing between the source of the wave the person acting a the observer.

Looking at the options given, this Doppler effect is applicable to: air traffic control where traffic controllers attempt to direct the traffic on the ground; weather forecasting where the conditions of the atmosphere at a particular time and place is being predicted; and in building inspection where we can use a non destructive test equipment known as Schmidt hammer to career out min destructive tests on a building.

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How are metal bridges built to cope with changes of temperature?

nirvana33 [79]

As the metal expands as does the road bed so neither really effevts those foing over the bridge. as it is hot the metal will expand and so will most tarmac on roads.

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3 years ago

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3 years ago

Calculate the difference in blood pressure between the feet and top of the head for a person who is 1.70 m tall.

cupoosta [38]

Answer:

$P_2 - P_1 = 1.8 * 10^4\ Pa$

Explanation:

Given

$Height (h) = 1.70m$

Required

Determine the difference in the blood pressure from feet to top

This is calculated using Pascal's second law.

The second law is represented as:

$P_2 = P_1 + pgd$

Subtract P1 from both sides

$P_2 - P_1 = pgd$

Where

$p = blood\ density = 1.06 * 10^3kg/m^3$

$g = acceleration\ of\ gravity = 9.8N/kg$

$d =height = 1.70m$

P2 - P1 = Blood Pressure Difference

So, the expression becomes:

$P_2 - P_1 = 1.06 * 10^3 * 9.8 * 1.70$

$P_2 - P_1 = 17659.6Pa$

$P_2 - P_1 = 1.8 * 10^4\ Pa$

Hence, the difference in blood pressure is approximately $1.8 * 10^4\ Pa$

3 0

3 years ago

Two equal charges with magnitude Q and Q experience a force of 12.3442 when held at a distance r. What is the force between two

andre [41]

Answer:

197.5072.

Explanation:

According to the Coulomb's law, the magnitude of the electrostatic force of interaction between two charges $\rm q_1$ and $\rm q_2$ which are separated by the distance $\rm d$ is given by

$\rm F = \dfrac{kq_1q_2}{d^2}.$

<em>where,</em> k is the Coulomb's constant.

For the case, when,

$\rm q_1 = Q.$
$\rm q_2 = Q.$
$\rm d=r.$
$\rm F=12.3442.$

Then, using Coulomb's law,

$\rm 12.3442 = \dfrac{kQQ}{r^2}=\dfrac{kQ^2}{r^2}\ \ \ \ .......\ (1).$

For the case, when,

$\rm q_1 = 2Q.$
$\rm q_2 = 2Q.$
$\rm d=\dfrac r2.$

Then, using Coulomb's law, the new electric force between the charges is given by,

$\rm F' = \dfrac{k(2Q)(2Q)}{\left (\dfrac r2\right )^2}\\=\dfrac{k\ 4Q^2}{\dfrac{r^2}{4}}\\=4\times 4 \times \dfrac{kQ^2}{r^2}\\=16\ \dfrac{kQ^2}{r^2}\\=16\times 12.3442\ \ \ \ \ \ \ \ (Using\ (1))\\=197.5072.$

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3 years ago

At what condition do a coin and feather fall together

Ronch [10]

Answer:

A feature and a coin dropped from the same height falls at the same speed at the condition at free fall,both coin and feature gain same acceleration of 9.8m/s^2.

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3 years ago