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Andreas93 [3]
3 years ago
13

Someone who is a girl friend me because I’m trying to get simp record

Physics
2 answers:
Lelu [443]3 years ago
6 0

Answer:

okay then

Explanation:

timurjin [86]3 years ago
3 0

Answer:

wdym

Explanation:

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The amplitude, or magnitude, of a sinusoidal source is the maximum value of the source. What is the amplitude of the voltage sou
liraira [26]

Answer:

<em>A = 0.05 V</em>

Explanation:

<u>Sinusoidal Functions</u>

A sinusoid or sinusoidal function is a sine or cosine which general equation is

F(x)=A.sin(wt-\phi)

Or also

F(x)=A.cos(wt-\phi)

Where A is the amplitude or maximum value, w is the angular frequency, t is the time and \phi is the phase shift.

Comparing the given expression with the general formula

v(t)=50cos(2000t-45^o) mV

We can establish that A=50 mV = 0.05 V

A = 0.05\ V

7 0
3 years ago
A small sphere is at rest at the top of a frictionless semicylindrical surface. The sphere is given a slight nudge to the right
V125BC [204]

Answer:

vi = 4.77 ft/s

Explanation:

Given:

- The radius of the surface R = 1.45 ft

- The Angle at which the the sphere leaves

- Initial velocity vi

- Final velocity vf

Find:

Determine the sphere's initial speed.

Solution:

- Newton's second law of motion in centripetal direction is given as:

                         m*g*cos(θ) - N = m*v^2 / R

Where, m: mass of sphere

             g: Gravitational Acceleration

             θ: Angle with the vertical

             N: Normal contact force.

- The sphere leaves surface at θ = 34°. The Normal contact is N = 0. Then we have:

                         m*g*cos(θ) - 0 = m*vf^2 / R

                         g*cos(θ) = vf^2 / R    

                         vf^2 = R*g*cos(θ)

                         vf^2 = 1.45*32.2*cos(34)

                        vf^2 = 38.708 ft/s

- Using conservation of energy for initial release point and point where sphere leaves cylinder:

                          ΔK.E = ΔP.E

                          0.5*m* ( vf^2 - vi^2 ) = m*g*(R - R*cos(θ))

                          ( vf^2 - vi^2 ) = 2*g*R*( 1 - cos(θ))

                          vi^2 =  vf^2 - 2*g*R*( 1 - cos(θ))

                          vi^2 = 38.708 - 2*32.2*1.45*(1-cos(34))

                          vi^2 = 22.744

                           vi = 4.77 ft/s

4 0
3 years ago
Please help me with this! :)
Bingel [31]
I can answer it in the comments, but can i ask what i’m supposed to do exactly? i remember learning about this stuff but i need the instructions.
8 0
2 years ago
How would you calculate an object’s mechanical energy? a. Add its kinetic and potential energies. b. Multiply its kinetic and po
dalvyx [7]
A. Add it's Kinetic and Potential energies
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3 years ago
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