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adell [148]
3 years ago
15

Find the 30th term of an arithmetic sequence whose first term is 2 and common difference is 5.

Mathematics
2 answers:
Veronika [31]3 years ago
3 0
2 + 29 times 5 = 147

Alina [70]3 years ago
3 0
First, create a formula for the arithmetic sequence.
a(n) = a(1) + d(n - 1)
a(n) = 2 + 5(n - 1)
a(30) = 2 + 5(29)
a(30) = 2 + 145
a(30) = 147

Hope that helps!
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Step-by-step explanation:

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IgorLugansk [536]
(y + 1)^3 would just be dividing the two

If you want it completely simplified, then it’s the following:

(y + 1)(y + 1)(y + 1)

= y^2 + y + y + 1 (y + 1)

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Suppose that the mean time that visitors stay at a museum is 94.2 minutes with a standard deviation of 15.5 minutes. The standar
Maurinko [17]

Answer:

94.2 -0.994*3.1 = 91.1186

94.2 +0.994*3.1 = 97.2814

And the 68% confidence interval is given by (91.1186, 97.2814)

Step-by-step explanation:

For this case we know that mean time that visitors stay at a museum is given by:

\bar X = 94.2

The standard deviation is given by:

s= 15.5

And the standard error is given by:

SE = \frac{s}{\sqrt{n}} =3.1

And we want to interval captures 68% of the means for random samples of 25 scores and for this case the critical value can be founded like this using the normal standard distribution or excel:

z_{\alpha/2}= \pm 0.994

We can find the interval like this:

\bar X \pm ME

And replacing we got:

94.2 -0.994*3.1 = 91.1186

94.2 +0.994*3.1 = 97.2814

And the 68% confidence interval is given by (91.1186, 97.2814)

7 0
3 years ago
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In this problem, we know the triangle's height,
but what is the length of the base ?

The base is the side that the triangle is sitting on.  This particular triangle
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4 years ago
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