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juin [17]
2 years ago
5

Hi can someon help me how to answer this? Btw I'm from Philippines

Physics
1 answer:
arlik [135]2 years ago
4 0

Answer:

Test 1

1.True

2.True

3.True

4.False

5.True

6.True

7.False

8.True

9.True

10.True

yung iba nasa pic

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It’s me again lol you’re questions are simple the formula is given in the triangle
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Please look at the attached image below for the explanation

5 0
2 years ago
A watermelon is dropped off of a 50 ft bridge, and it explodes upon impact with the ground. How fast was it traveling in mph upo
Drupady [299]

Answer: 56.72 ft/s

Explanation:

Ok, initially we only have potential energy, that is equal to:

U =m*g*h

where g is the gravitational acceleration, m the mass and h the height.

h = 50ft and g = 32.17 ft/s^2

when the watermelon is near the ground, all the potential energy is transformed into kinetic energy, and the kinetic energy can be written as:

K = (1/2)*m*v^2

where v is the velocity.

Then we have:

K = U

m*g*h = (m/2)*v^2

we solve it for v.

v = √(2g*h) = √(2*32.17*50) ft/s = 56.72 ft/s

6 0
3 years ago
A subway train accelerates from rest at one station at a rate of 1.30 m/s^2 for half of the distance to the next station, then d
Minchanka [31]

This problems a perfect application for this acceleration formula:

         Distance = (1/2) (acceleration) (time)² .

During the speeding-up half:     1,600 meters = (1/2) (1.3 m/s²) T²
During the slowing-down half:    1,600 meters = (1/2) (1.3 m/s²) T²

Pick either half, and divide each side by  0.65 m/s²: 

                         T² = (1600 m) / (0.65 m/s²)

                         T = square root of (1600 / 0.65) seconds

Time for the total trip between the stations is double that time.

                         T =  2 √(1600/0.65) = <em>99.2 seconds</em>  (rounded)


7 0
3 years ago
A circular loop in the plane of a paper lies in a 0.45 T magnetic field pointing into the paper. The loop's diameter changes fro
Amanda [17]

Answer:

(A). The direction of the induced current will be clockwise.

(B). The magnitude of the average induced emf 16.87 mV.

(C). The induced current is 6.75 mA.

Explanation:

Given that,

Magnetic field = 0.45 T

The loop's diameter changes from 17.0 cm to 6.0 cm .

Time = 0.53 sec

(A). We need to find the direction of the induced current.

Using Lenz law

If the direction of magnetic field shows into the paper then the direction of the induced current will be clockwise.

(B). We need to calculate the magnetic flux

Using formula of flux

\phi_{1}=BA\cos\theta

Put the value into the formula

\phi_{1}=0.45\times(\pi\times(8.5\times10^{-2})^2)\cos0

\phi_{1}=0.01021\ Wb

We need to calculate the magnetic flux

Using formula of flux

\phi_{2}=BA\cos\theta

Put the value into the formula

\phi_{2}=0.45\times(\pi\times(3\times10^{-2})^2)\cos0

\phi_{2}=0.00127\ Wb

We need to calculate the magnitude of the average induced emf

Using formula of emf

\epsilon=-N(\dfrac{\Delta \phi}{\Delta t})

Put the value into t5he formula

\epsilon=-1\times(\dfrac{0.00127-0.01021}{0.53})

\epsilon=0.016867\ V

\epsilon=16.87\ mV

(C). If the coil resistance is 2.5 Ω.

We need to calculate the induced current

Using formula of current

I=\dfrac{\epsilon}{R}

Put the value into the formula

I=\dfrac{0.016867}{2.5}

I=0.00675\ A

I=6.75\ mA

Hence, (A). The direction of the induced current will be clockwise.

(B). The magnitude of the average induced emf 16.87 mV.

(C). The induced current is 6.75 mA.

5 0
3 years ago
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