13•[18 divided by (15-9)} Evaluate
1 answer:
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Answer:
1. The chi-squared statistic = 10.36
The degrees of freedom = 17
The p-value for the test = 0.89
2. The range of the p-value from the Chi squared table = 0.75 < p-value < 0.90
Step-by-step explanation:
1. The Chi squared test is given as follows;
Therefore,
UTI No UTI % Total
Cranberry juice 8 42 84 50
Lactobacillus 19 30 61 49
Control 18 30 60 50
The chi-squared statistic is given as follows;
The chi-squared statistic = 10.36
The degrees of freedom, df = 18 - 1 = 17 since the all of the expected count have a minimum value of 18
With the aid of the calculator we find the p value as p as follows;
The p-value for the test = 0.89
2. The range of the p-value from the Chi squared table is given as follows;
0.75 < p-value < 0.90.
Answer:
Fishing lure will be at a height of 12 feet after 0.19 and 1.31 seconds
Step-by-step explanation:
Travel of a fishing lure has been given by the expression,
h = -16t + 24t + 4
where h = height of the fishing lure
t = time or duration of travel
Height traveled by the fishing lure = 12 - 4 = 8 feet
For h = 8 feet,
8 = -16t² + 24t + 4
-16t² + 24t + 4 - 8 = 0
16t² - 24t + 4 = 0
4t² - 6t + 1 = 0
t =
=
=
=
= 1.31, 0.19 seconds