At 100 km/hr, the car's kinetic energy is
KE = (1/2) (mass) (speed)²
KE = (1/2) (1575 kg) ( [100 km/hr] x [1000 m/km] x [1 hr/3600 sec] )²
KE = (787.5 kg) (27.78 m/s)²
KE = 607,639 Joules
In order to deliver this energy in 2.9 seconds, the engine must supply
(607,639 J / 2.9 sec) = 209,531 watts
<em>Power = 281 HP</em>
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Answer:
15186 J energy lost due to friction
Explanation:
Given:
- Height of the tallest hill (first) h_1 = 16 m
- Height of the last hill h_2 = 7 m
- Velocity @tallest hill = 0
- Velocity @last hill = 0
Find:
How much energy was lost due to friction can be determined from an energy balance at point on top of tallest hill and on top of last hill:
E_p,1 + E_k,1 = E_p,2 + E_k,2 + E_f
Where, E_k,1 = E_k,2 = 0
E_p,1 - E_p,2 = E_f
E_f = m*g*(h_1 - h_2)
E_f = 172*9.81*(16 - 7)
E_f = 15186 J
Power can be expressed by the product of current and voltage. To see this, consider the units of current and voltage:
Where C is coulombs (charge), s is seconds, J is joules (energy), and W is Watts, or power. See that watts are Joules per second, or the time rate of change of energy.
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