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NNADVOKAT [17]
3 years ago
7

Jack and jill blow their whistles at the same time producing sound waves at frequencies of 400 hz and 404 hz respectively. how m

any beats per second are heard from the superposition of the two waves
Physics
2 answers:
Lera25 [3.4K]3 years ago
3 0

When two sound waves of similar frequency interfere with each other, there is a fluctuating sound heard which is periodic and repeating. This fluctuating sound is called beat. Beat frequency( number of beats per second) is equal to the difference of the frequency of the two sound waves.

So, sound waves of frequency 400 Hz and 404 Hz will produce 4 beats per second.

joja [24]3 years ago
3 0

Two beat sounds are produced, at the sum and difference of the two waves that produce them.

When Jack and Jill blow their whistles at the same time, their father Joe, at the bottom of the hill, hears four sounds ... the sound from Jack's whistle at 400 Hz, the sound from Jill's whistle at 404 Hz, and two more sounds that have no apparent source ... one at 804 Hz and another at 4 Hz.

Joe may not even notice the sound at 804 Hz, and the 4 Hz won't actually sound like a sound ... it'll sound to Joe like a rapid pulsing fluctuation in the loudness of the sounds from the whistles.

As long as the sounds of the whistles and their beats continue, Joe knows that the kids are OK, but they're not doing the job he sent them up the hill to do. Clearly, they're standing there whistling, and no pail of water is being fetched.

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Answer:

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7 0
3 years ago
The radius of earth is 6,370,000 m. Express this measurement in km in scientific notation with the correct number of significant
AlexFokin [52]

Answer:

6.37 x 10³ Km

Explanation:

given,

Radius of earth = 6,370,000 m

we know,

1 km = 1000 m

1 m = 0.001 Km

6,370,000 m =  6,370,000 x 0.001

                       = 6,370 Km

The number 6,370 has 3 significant figure.

To transform this to an exponential number, it is necessary to move the decimal to the left so there is only one digit in front of the decimal point.

Representing the given number in scientific notation

      = 6.37 x 10³ Km

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3 years ago
A girl (mass M) standing on the edge of a frictionless merry-go-round (radius R, rotational inertia I) that is not moving. She t
vladimir1956 [14]

a) \omega=\frac{-mvR}{I+MR^2}

b) v=\frac{-mvR^2}{I+MR^2}

Explanation:

a)

Since there are no external torques acting on the system, the total angular momentum must remain constant.

At the beginning, the merry-go-round and the girl are at rest, so the initial angular momentum is zero:

L_1=0

Later, after the girl throws the rock, the angular momentum will be:

L_2=(I_M+I_g)\omega +L_r

where:

I is the moment of inertia of the merry-go-round

I_g=MR^2 is the moment of inertia of the girl, where

M is the mass of the girl

R is the distance of the girl from the axis of rotation

\omega is the angular speed of the merry-go-round and the girl

L_r=mvR is the angular momentum of the rock, where

m is the mass of the rock

v is its velocity

Since the total angular momentum is conserved,

L_1=L_2

So we find:

0=(I+I_g)\omega +mvR\\\omega=\frac{-mvR}{I+MR^2}

And the negative sign indicates that the disk rotates in the direction opposite to the motion of the rock.

b)

The linear speed of a body in rotational motion is given by

v=\omega r

where

\omega is the angular speed

r is the distance of the body from the axis of rotation

In this problem, for the girl, we have:

\omega=\frac{-mvR}{I+MR^2} is the angular speed

r=R is the distance of the girl from the axis of rotation

Therefore, her linear speed is:

v=\omega R=\frac{-mvR^2}{I+MR^2}

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