The correct option is
a. Acetyl-CoA combines with a pyruvic acid to make glucose in the Krebs cycle.
Explanation:
The Krebs citric acid cycle happens within the mitochondrial matrix and generates a pool of energy (ATP, NADH, and FADH2) from the oxidization of pyruvate, the tip product of metabolism. Pyruvate is transported into the mitochondria and loses dioxide to make acetyl-CoA, a 2-carbon molecule.
The egg is transferred from the ovary to the uterus through muscle contractions called uterine contractions by using special hair like structures called cilia.
Answer:
1) The force Christian can exert on his bicycle before picking up the the cargo is 529.74 N
2) The force Christian can exert on his bicycle after picking up the the cargo is 647.46 N
Therefore, Christian has to exert more force on his bike after picking up the cargo
Explanation:
The given parameters are;
The mass of Christian and his bicycle = 54 kg
The mass of the cargo = 12 kg
1) The force Christian can exert on his bicycle before picking up the the cargo = Mass of Christian and his bicycle × Acceleration due to gravity
∴ The force Christian can exert on his bicycle before picking up the the cargo = 54 kg × 9.81 m/s² = 529.74 N
2) The force Christian can exert on his bicycle after picking up the the cargo = (54 + 12) kg × 9.81 m/s² = 647.46 N
Therefore, Christian has to exert more force on his bike after picking up the cargo.
No I don’t think so. But it worth a try tho. Try it out.
Answer:Shifted towards Left by distance of 2.243 m
Explanation:
Given
Mass of john ![m_1=95.6 kg](https://tex.z-dn.net/?f=m_1%3D95.6%20kg)
Mass of barbara ![m_2=55.3 kg](https://tex.z-dn.net/?f=m_2%3D55.3%20kg)
John is standing at ![x=10.9 m](https://tex.z-dn.net/?f=x%3D10.9%20m)
Barbara is standing at ![x=2.50 m](https://tex.z-dn.net/?f=x%3D2.50%20m)
![x_{com}=\frac{m_1x_1+m_2x_2}{m_1+m_2}](https://tex.z-dn.net/?f=x_%7Bcom%7D%3D%5Cfrac%7Bm_1x_1%2Bm_2x_2%7D%7Bm_1%2Bm_2%7D)
![x_{com}=\frac{95.6\times 10.9+55.3\times 2.5}{95.6+55.3}](https://tex.z-dn.net/?f=x_%7Bcom%7D%3D%5Cfrac%7B95.6%5Ctimes%2010.9%2B55.3%5Ctimes%202.5%7D%7B95.6%2B55.3%7D)
![x_{com}=\frac{1180.29}{150.9}](https://tex.z-dn.net/?f=x_%7Bcom%7D%3D%5Cfrac%7B1180.29%7D%7B150.9%7D)
![x_{com}=7.821 m](https://tex.z-dn.net/?f=x_%7Bcom%7D%3D7.821%20m)
Now if they change their Position then
![x'_{com}=\frac{95.6\times 2.5+55.3\times 10.9}{95.6+55.3}](https://tex.z-dn.net/?f=x%27_%7Bcom%7D%3D%5Cfrac%7B95.6%5Ctimes%202.5%2B55.3%5Ctimes%2010.9%7D%7B95.6%2B55.3%7D)
![x'_{com}=\frac{841.77}{150.9}](https://tex.z-dn.net/?f=x%27_%7Bcom%7D%3D%5Cfrac%7B841.77%7D%7B150.9%7D)
![x'_{com}=5.578](https://tex.z-dn.net/?f=x%27_%7Bcom%7D%3D5.578)
Thus we can see that center of mass shifted towards left by a distance of
because heavier is shifted towards left