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crimeas [40]
4 years ago
9

If you stood on a planet with four times the mass of Earth, and twice Earth's radius, how much would you weigh?

Physics
1 answer:
nikdorinn [45]4 years ago
3 0

Answer:

1/4 times your earth's weight

Explanation:

assuming the Mass of earth = M

Radius of earth = R

∴ the mass of the planet= 4M

the radius of the planet = 4R

gravitational force of earth is given as = \frac{GM}{R^{2} }

where G is the gravitational constant

Gravitational force of the planet = \frac{G4M}{(4R)^{2} }

                                                       =\frac{G4M}{16R^{2} }

                                                       =\frac{GM}{4R^{2} }

recall, gravitational force of earth is given as = \frac{GM}{R^{2} }

∴Gravitational force of planet = 1/4 times the gravitational force of the earth

you would weigh 1/4 times your earth's weight

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In fact, the IMA and the AMA of a machine are defined as the ratio between the output force (the load) and the input force (the effort):
IMA= \frac{F_{out}}{F_{in}}
however, the difference is that the IMA does not take into account the presence of frictions, while the AMA does. As a result, the output force in the AMA is less than the output force in the IMA (because some energy is dissipated due to friction), and the AMA is less than the IMA.
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3 years ago
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Can a body have mass but no weight give reasion for your answer​
EleoNora [17]

Answer:

Hey buddy, here is your answer. Hope it helps you.

Explanation:

Yes, weight of a body is not constant, it varies with the value of acceleration due to gravity, g. Weight of a body is zero, when it is taken to the centre of the earth or in the interplanetary space, where g=0. Mass is the total matter in a body, while weight is the force by which the body is attracted.

Weight is never constant while mass is. So we can have weight zero but with some mass. This will happen when an object is at the centre of earth, as g=0 at centre of earth , so weight will be 0 while mass will always be constant everywhere

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3 years ago
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Puede ser la suma de dos vectores de distinta magnitud igual a 0
True [87]

Answer:

Falso. Se requiere de dos vectores de igual magnitud pero antiparalelos entre sí.

Explanation:

Un vector es un elemento caracterizado por tener magnitud y dirección, sea \vec v \in \mathbb{R} un vector tal que la resultante sea \vec O (vector nulo). Por Álgebra de los Reales se sabe que todo vector tiene su inverso, es decir, que existe un vector -\vec v tal que:

\vec v + (-\vec v) = \vec O

(v_{x}, v_{y}) + [-(v_{x},v_{y})] = (0,0)

(v_{x}-v_{x}, v_{y}-v_{y}) = (0, 0)

Esto significa, que el siguiente sistema de ecuaciones debe satisfacerse:

v_{x}-v_{x} = 0

v_{y}-v_{y} = 0

Se requiere de dos vectores de igual magnitud pero antiparalelos entre sí. En consecuencia, la anterior afirmación es falsa.

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3 years ago
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kvv77 [185]

Answer:

16

Explanation:

300/18.75

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3 years ago
The energy released by the exploding gunpowder in a cannon propels the cannonball forward. Simultaneously the cannon recoils. Wh
Neporo4naja [7]

Answer:

The launched cannonball

Explanation:

Consider,

The mass of the cannonball, m

The mass of the cannon, M =  1000 m

The velocity of the cannon, V

The velocity of the cannonball, v = 100 V

The K.E of the cannon, K.E = ½ MV²

The K.E of the cannonball, k.e = ½ mv²

Substituting the values in the K.E of the cannon

                                     ½ MV² = ½ x 1000 m x (v/100² )

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Therefore,                    ½ mv² = 10 x  ½ MV²

The K.E of the cannonball is 10 times the K.E of the cannon.

Hence, the cannonball has a grater K.E

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3 years ago
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