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Bezzdna [24]
3 years ago
9

What special day is when Massachusetts receives the most indirect rays of the sun?

Physics
1 answer:
viva [34]3 years ago
6 0

In December solstice Massachusetts receives the most indirect rays of the sun. It happened on the day of 21st of December.

<u>Explanation</u>:

Winter solstice festivities bring "stillness, light, and warmth" into this period of the occasion hustle. Keeping that in mind, we give you this gathering of mysterious occasions to stamp the day of the year (this year, Friday, December 21) with the briefest time of sunlight and the longest night of year. Also, obviously, to respect the arrival of the sun and the more extended days to come.

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The same pipe is used to carry both air and water. For the same fluid velocity and friction factor for the air and water flows:
VladimirAG [237]

Answer:

the pressure drop for the water flow is greater than that for the air flow.

Explanation:

Detailed analysis of the problem is show below.

4 0
3 years ago
Which describes electricity?
SVETLANKA909090 [29]

Answer:

all of the above

Explanation:

- a build up of electric charge

- the force and motion of electrically charged particles

- an electric current

are three different ways to describe electricity.

So the answer is all of the above.

7 0
2 years ago
What is the potential energy of a 45 kg object resting on the ground?
yKpoI14uk [10]

Answer:The potential energy is zero

Explanation:

3 0
3 years ago
A 150-N box is being pulled horizontally in a wagon accelerating uniformly at 3.00 m/s2. The box does not move relative to the w
Zepler [3.9K]

Answer:

Frictional force, F = 45.9 N

Explanation:

It is given that,

Weight of the box, W = 150 N

Acceleration, a=3\ m/s^2

The coefficient of static friction between the box and the wagon's surface is 0.6 and the coefficient of kinetic friction is 0.4.  

It is mentioned that the box does not move relative to the wagon. The force of friction is equal to the applied force. Let a is the acceleration. So,

m=\dfrac{W}{g}

m=\dfrac{150}{9.8}

m=15.3\ kg

Frictional force is given by :

F=ma

F=15.3\times 3

F = 45.9 N

So, the friction force on this box is closest to 45.9 N. Hence, this is the required solution.

8 0
3 years ago
A 1.5-kg mass attached to an ideal massless spring with a spring constant of 20.0 N/m oscillates on a horizontal, frictionless t
Molodets [167]

Answer:

Explanation:

a ) angular frequency ω = \sqrt{\frac{k}{m} }

k is spring constant and m is mass attached

ω = \sqrt{\frac{20}{1.5} }

= 3.6515 rad / s

frequency of oscillation n = 3.6515 / (2 x 3.14)

= .5814 s⁻¹

x = .1 mcos(ωt)

= .1 mcos(3.6515t)

b ) maximum speed = ωA , A is amplitude

= 3.6515 x .1

= .36515 m /s

36.515 cm /s

maximum acceleration = ω²A

= 3.6515² x .1

= 1.333 m / s²

c ) Kinetic energy at displacement x

= 1/2 m ω²( A²-x²)

potential energy =1/2 m ω²x²

so 1/2 m ω²( A²-x²) = 1/2 m ω²x²

A²-x² = x²

2x² = A²

x = A / √2

6 0
3 years ago
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