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Bezzdna [24]
3 years ago
9

What special day is when Massachusetts receives the most indirect rays of the sun?

Physics
1 answer:
viva [34]3 years ago
6 0

In December solstice Massachusetts receives the most indirect rays of the sun. It happened on the day of 21st of December.

<u>Explanation</u>:

Winter solstice festivities bring "stillness, light, and warmth" into this period of the occasion hustle. Keeping that in mind, we give you this gathering of mysterious occasions to stamp the day of the year (this year, Friday, December 21) with the briefest time of sunlight and the longest night of year. Also, obviously, to respect the arrival of the sun and the more extended days to come.

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Question 17 A sample of iron is put into a calorimeter (see sketch at right) that contains of water. The iron sample starts off
ivanzaharov [21]

Complete Question:

A 59.1 g sample of iron is put into a calorimeter (see sketch attached) that contains 100.0 g of water. The iron sample starts off at 85.0 °C and the temperature of the water starts off at 23.0 °C. When the temperature of the water stops changing it's 27.6 °C. The pressure remains constant at 1 atm.

Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits

(Question attached)

Answer:

c_{iron}=0.568 J/kg.\°C

c_{iron}=0.6 J/kg.\°C (rounded to 1 decimal place)

Explanation:

A calorimeter is used to measure the heat of chemical or physical reactions. The example given in the question is using the calorimeter to determine the specific heat capacity of iron.

When the system reaches equilibrium the iron and water will be the same temperature, T_{e}. The energy lost from the iron will be equal to the energy gained by the water. It is assumed that the only heat exchange is between the iron and water and no exchange with the surroundings.

Q=mc(T_{e}-T_{initial}) (Eq 1)

-Q_{iron}=Q_{water} (Eq 2)

Water:

m_{water}=100.0 g, c_{water}=4.186 J/kg.\°C, T_{initial,water}=23 \°C, T_{e}=27.6 \°C

Iron:

m_{iron}=59.1 g, c_{iron} = ? J/kg.\°C, T_{initial,iron}=85 \°C, T_{e}=27.6 \°C

Substituting Eq 1 into Eq 2 and details extracted from the question:

-m_{iron}c_{iron}(T_{iron,e}-T_{initial})=m_{water}c_{water}(T_{water,e}-T_{initial})

-59.1*c_{iron}(27.6-85)=100.0*4.186(27.6-23)

c_{iron}=0.568 J/kg.\°C

c_{iron}=0.6 J/kg.\°C

4 0
3 years ago
What is the mass of an object if a force of 34 N produces an acceleration of 4 m/s/s?
antoniya [11.8K]
Use newton's second law, F = ma.
Force is 34 N and a is 4 m/s/s
34 = m(4), solve for m.
34/4 = 8.5 g
8 0
3 years ago
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