All categories

3 years ago

Which phrases describe what the rock cycle shows? Check all that apply.

Chemistry

1 answer:

Ne4ueva [31]3 years ago

7 0

Answer:

A. Any type of rock can change into any other type of rock by weathering and erosion.

C. Rocks change slowly over time.

D. The rock cycle shows how the three rock types relate to one another.

You might be interested in

All matter has __. A.) COLOR B.) MASS C.) VOLUME D.) WEIGHT

Firlakuza [10]

I'm pretty sure it's B) Mass

3 0

3 years ago

Calculate moles of Fe in 5.22 X 10^22 atoms of Fe?

Setler [38]

Answer:

The amount of moles of Fe in 5.22*10²² atoms of Fe is 0.0867.

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 6.023*10²³ atoms are contained in 1 mole, 5.22*10²² atoms are contained in how many moles?

$amount of moles=\frac{5.22*10^{22}atoms * 1 mole}{6.023*10^{23}atoms}$

amount of moles= 0.0867

The amount of moles of Fe in 5.22*10²² atoms of Fe is 0.0867.

5 0

2 years ago

W7L5 Stoichiometry Practice 2

Rzqust [24]

Answer:

.079 moles of Nirogen gas (N2)

Explanation:

You can see from the equaton that each ONE mole of N2 produces TWO moles of NH3.

Find the number of moles of NH3 produced.

Using Periodic Table : Mole wt of NH3 = 17 gm/mole

2.7 gm / 17 gm/mole = .1588 moles

One half as many moles of N2 are needed = .079 moles

6 0

2 years ago

Water has a boiling point of 100.0°C and a Kb of 0.512°C/m. What is the boiling

Reil [10]

Answer:

The boiling point of a 8.5 m solution of Mg3(PO4)2 in water is 394.91 K.

Explanation:

The formula for molal boiling Point elevation is :

$\Delta T_{b} = iK_{b}m$

$\Delta T_{b}$ = elevation in boiling Point

$K_{b}$ = Boiling point constant( ebullioscopic constant)

m = molality of the solution

i = Van't Hoff Factor

Van't Hoff Factor = It takes into accounts,The abnormal values of Temperature change due to association and dissociation .

In solution Mg3(PO4)2 dissociates as follow :

$Mg_{3}(PO_{4})_{2}\rightarrow 3Mg^{2+} + 2 PO_{4}^{3-}$

Total ions after dissociation in solution :

= 3 ions of Mg + 2 ions of phosphate

Total ions = 5

i = Van't Hoff Factor = 5

m = 8.5 m

$K_{b}$ = 0.512 °C/m

Insert the values and calculate temperature change:

$\Delta T_{b} = iK_{b}m$

$\Delta T_{b} = 5\times 0.512\times 8.5$

$\Delta T_{b} = 21.76 K$

Boiling point of pure water = 100°C = 273.15 +100 = 373.15 K

$\Delta T_{b} = T_{b} - T_{b}_{pure}$

$T_{b}_{pure}$ = 373.15 K[/tex]

21.76 = T - 373.15

T = 373.15 + 21.76

T =394.91 K

8 0

3 years ago

Calculate the mass in grams for each of the following liquids.

WITCHER [35]

The density is calculated as mass per volume, so if we want to solve for mass, we would multiply density by volume.
For Part A: if we have a density of 0.69 g/mL, and a volume of 280 mL, multiplying these will give a mass of: (0.69 g/mL)(280 mL) = 193.2 g. Rounded to 2 significant figures, this is 190 g gasoline.
For Part B: if we have a density of 0.79 g/mL, and a volume of 190 mL, multiplying these will give a mass of: (0.79 g/mL)(190 mL) = 150.1 g. Rounded to 2 significant figures, this is equal to 150 g ethanol.

3 0

3 years ago