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oee [108]
2 years ago
7

What volume is occupied by 0.104 mol of helium gas at a pressure of 0.91 atm and a temperature of 314 K ?

Chemistry
1 answer:
Aleksandr-060686 [28]2 years ago
7 0

Answer:

The volume will be "2.95 L".

Explanation:

Given:

n = 0.104

p = 0.91 atm

T = 314 K

Now,

The Volume (V) will be:

= \frac{nRT}{P}

By putting the values, we get

= \frac{0.104\times 0.0821\times 314}{0.91}

= \frac{2.6810}{0.91}

= 2.95 \ L

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