Question

What volume is occupied by 0.104 mol of helium gas at a pressure of 0.91 atm and a temperature of 314 K ?

Answer 1

Answer:

The volume will be "2.95 L".

Explanation:

Given:

n = 0.104

p = 0.91 atm

T = 314 K

Now,

The Volume (V) will be:

= $\frac{nRT}{P}$

By putting the values, we get

= $\frac{0.104\times 0.0821\times 314}{0.91}$

= $\frac{2.6810}{0.91}$

= $2.95 \ L$