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tekilochka [14]
3 years ago
10

4. Ron and Hermoine are fighting over the Monster book of Monsters and they are both pulling on the book with a force of 14 N (e

qually and in opposite directions). What will happen to the book in this situation? A) The book will slide towards Ron B) The book will slide towards Hermoine C) The book will fly up in the air D) The book will not move
Physics
2 answers:
marysya [2.9K]3 years ago
5 0

D. The book will not move.

When two forces are pulling against each other with equal force, there is no movement since they will both cancel each other out.

V125BC [204]3 years ago
4 0

the correct answer is D. we went over in class

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Answer:

longitudinal and transverse.

Explanation:

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2 years ago
A woman experiences an electrical shock. The electrons making the shock come from the A woman experiences an electrical shock. T
Zinaida [17]

The electrons making the shock come from the women's body.

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The nervous system may be impacted by a shock.

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7 0
1 year ago
Use your periodic table to answer the following question.
Pavel [41]
Helium has only 2 electrons in it's valence shell

So, option D is your answer.

Hope this helps!
6 0
3 years ago
A vertical block-spring system on earth has a period of 6.0 s. What is the period of this same system on the moon where the acce
Vera_Pavlovna [14]

Answer:

D) 15s

Explanation:

let Te be the period of the block-spring system on earth and Tm be the period of the same system on the moon.let g1 be the gravitational acceleration on earth and g2 be the gravitational acceleration on the moon.

the period of a pendulum is given by:

T = 2π√(L/g)

so on earth:

Te = 2π√(L/g1)

     =  6s

on the moon;

Tm = 2π√(L/g2)

since g2 = 1/6 g1 then:

Tm = 2π√(L/(1/6×g1))

      = √(6)×2π√(L/(g1))

and 2π√(L/(g1)) = Te = 6s

Tm = (√(6))×6 = 14.7s ≈ 15s

Therefore, the period of the block-spring system on the moon is 15s.

5 0
3 years ago
When you push a 2.00 kg book resting on a tabletop it takes 4.60 N to start the book sliding. What is the coefficient of static
natali 33 [55]

The coefficient of static friction is 0.234.

Answer:

Explanation:

Frictional force is equal to the product of coefficient of friction and normal force acting on any object.

So here the mass of the object is given as 2 kg, so the normal force will be acting under the influence of acceleration due to gravity.

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Normal force = 2 * 9.8 = 19.6 N.

And the frictional force is given as 4.6 N, then

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Coefficient of static friction = 4.6 N / 19.6 N = 0.234

So the coefficient of static friction is 0.234.

3 0
2 years ago
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