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tekilochka [14]
3 years ago
10

4. Ron and Hermoine are fighting over the Monster book of Monsters and they are both pulling on the book with a force of 14 N (e

qually and in opposite directions). What will happen to the book in this situation? A) The book will slide towards Ron B) The book will slide towards Hermoine C) The book will fly up in the air D) The book will not move
Physics
2 answers:
marysya [2.9K]3 years ago
5 0

D. The book will not move.

When two forces are pulling against each other with equal force, there is no movement since they will both cancel each other out.

V125BC [204]3 years ago
4 0

the correct answer is D. we went over in class

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What has research determined about the orbit of an electron around a nucleus?
sergeinik [125]
The one that research has determined about the orbit of an electron around nucleus is : Each sub-level electron type has a unique path where it will likely to be found
Here are the sub levels of an electron :
-sub level s, maximum number of 2 electrons
- sub level p, maximum number of 6 electrons
- sub level d, maximum number of 10 electrons
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8 0
3 years ago
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What is power?
e-lub [12.9K]

Answer:

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4 years ago
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A. Draw four rays parallel to the optical axis of your mirror. Two above the optic axis and two below it.
Katen [24]

Answer:

   f = q

Explanation:

In the attachment we can see a diagram of the parallel rays.

The dotted line represents the normal to the mirror surface

These rays when reflected using the constructor equation

        \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

where p and q are the distance to the object and the image respectively.

Since the rays are parallel P = inf

          1 / f = 1 / inf + 1 / q

          f = q

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6 0
3 years ago
Does mercury have more protons and electrons than tin
Klio2033 [76]
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3 years ago
What must be the pressure difference between the two ends of a 2.6 km section of pipe, 36 cm in diameter, if it is to transport
ad-work [718]

Answer: 1.13(10)^{3} Pa

Explanation:

This problem can be solved by the following equation:

\Delta P=\frac{8 \eta L Q}{\pi r^{4}}

Where:

\Delta P is the pressure difference between the two ends of the pipe

\eta=0.20 Pa.s is the viscosity of oil

L=2.6 km=2600 m is the length of the pipe

Q=900 \frac{cm^{3}}{s} \frac{1 m^{3}}{(100 cm)^{3}}=0.0009 \frac{m^{3}}{s} is the Rate of flow of the fluid

d=36 cm=0.36 m is the diameter of the pipe

r=\frac{d}{2}=0.18 m is the radius of the pipe

Soving for \Delta P:

\Delta P=\frac{8 (0.20 Pa.s)(2600 m)(0.0009 \frac{m^{3}}{s})}{\pi (0.18 m)^{4}}

Finally:

\Delta P=1135.26 Pa \approx 1.13(10)^{3} Pa

7 0
3 years ago
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