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2 years ago

What occurs during the recharge process? Why is recharging with a salt brine solution that

Chemistry

1 answer:

Elodia [21]2 years ago

3 0

Answer:

During the recharge process, the water infiltrates at the land's surface and flows through the unsaturated zone. It then crosses the water table and enters the groundwater system. Chloride (NaCl) is important and necessary because the sodium ions are held loosely and exchanged easily with calcium and magnesium ions.

Explanation:

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A 100.0 mL sample of a 0.200 M aqueous solution of K2CrO4 was added to 100.0 mL of a 0.100 M aqueous solution of BaCl2. The mixt

stepan [7]

The correct answer is 2.53 g of precipitate, BaCrO4.

5 0

2 years ago

A 0.200 g sample of unknown metal x is dropped into hydrochloride acid and realeases 80.3 mL of hydrogen gas at STP using ideal

s344n2d4d5 [400]

Answer:

The number of mole of the unknown metal is 3.58×10¯³ mole

Explanation:

We'll begin by calculating the number of mole hydrogen gas, H2 that will occupy 80.3 mL at stp.

This is illustrated below:

Recall:

1 mole of any occupy 22.4L or 22400 mL at stp.

1 mole of H2 occupies 22400 mL at stp.

Therefore, Xmol of H2 will occupy 80.3 mL at stp i.e

Xmol of H2 = 80.3/22400

Xmol of H2 = 3.58×10¯³ mole

Therefore, 3.58×10¯³ mole of Hydrogen gas was released.

Now, we can determine the mole of the unknown metal as follow:

The balanced equation for the reaction is given below:

X + 2HCl —> XCl2 + H2

From the balanced equation above,

1 mole of the unknown metal reacted to produce 1 mole of H2.

Therefore, 3.58×10¯³ mole of the unknown metal will also react to produce 3.58×10¯³ mole of H2.

Therefore, the number of mole of the unknown compound is 3.58×10¯³ mole.

5 0

2 years ago

Calculate the amount of grams of water that was used when 5525J of energy was used to boil this amount of water.

djverab [1.8K]

Answer:

2.445 g

Explanation:

Step 1: Given and required data

Energy in the form of heat required to boil the water (Q): 5525 J

Latent heat of vaporization of water (∆H°vap): 2260 J/g

Mass of water (m): ?

Step 2: Calculate the mass of water

We will use the following expression.

Q = ∆H°vap × m

m = Q / ∆H°vap

m = 5525 J / (2260 J/g)

m = 2.445 g

4 0

2 years ago

A 2.5 L flask is filled with 0.25 atm SO3, 0.20 atm SO2, and 0.40 atm O2, and allowed to reach equilibrium. Assume at the temper

Anit [1.1K]

Explanation:

Reaction equation for the given chemical reaction is as follows.

$2SO_{3} \rightleftharpoons 2SO_{2} + O_{2}$

Equation for reaction quotient is as follows.

Q = $\frac{P^{2}_{SO_{2}} \times P_{O_{2}}}{P^{2}_{SO_{3}}}$

= $\frac{(0.20)^{2} \times 0.40}{(0.25)^{2}}$

= 0.256

As, Q > K (= 0.12)

The effect on the partial pressure of $SO_{3}$ as equilibrium is achieved by using Q, is as follows.

This means that there are too much products.

Equilibrium will shift to the left towards reactants.

More $SO_{3}$ is formed.

Partial pressure of $SO_{3}$ increases.

4 0

3 years ago

(02.01 MC)

Rina8888 [55]

Answer:

C. Particle size

Explanation:

The sand, which has smaller particles, will go through the sieve, while the rice (with a larger particle size) will not

4 0

2 years ago