In a liquid with a density of 1500 kg/m3, longitudinal waves with a frequency of 410 Hz are found to have a wavelength of 7.80 m
1 answer:
Answer:
The bulk modulus of the liquid is 1.534 x 10¹⁰ N/m²
Explanation:
Given;
density of the liquid, ρ = 1500 kg/m³
frequency of the wave, F = 410 Hz
wavelength of the sound, λ = 7.80 m
The speed of the wave is calculated as;
v = Fλ
v = 410 x 7.8
v = 3,198 m/s
The bulk modulus of the liquid is calculated as;
Therefore, the bulk modulus of the liquid is 1.534 x 10¹⁰ N/m²
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Answer:
Speed:
Wavelength:
Frequency:
Explanation:
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Where c is the speed of light and v is the speed of the laser in the medium.
Therefore, v will be isolated from equation 1
Hence, the speed of the laser has a value of
Frenquency:
Since, wavelength is the only one who depends on the media. Therefore the frequency in both medium will be the same.
To determine the frequency it can be used the following equation
(2)
Where c is the speed of light, is the frequency and
is the wavelength
Then, wil be isolated from equation 2.
(3)
Before using equation 3 it is necessary to express in units of meters.
⇒
Hence, the frequency of the laser has a value of
Wavelength:
To determine the wavelength it can be used:
Where v is the speed of the laser through the polystyrene.
Hence, the wavelength of the laser has a value of
Answer:
<em>Part A</em><em>:</em>
a) If the wavelength of the light is decreased the fringe spacing Δy will decrease.
<em>Part B</em><em>:</em>
b) If the spacing between the slits is decreased the fringe spacing Δy will increase.
<em>Part C</em><em>:</em>
a) If the distance to the screen is decreased the fringe spacing will decrease.
<em>Part D</em><em>:</em>
The dot in the center of fringe E is farther from the left slit than from the right slit.
Explanation:
In the double-slit experiment there is a clear contrast between the dark and bright fringes, that indicate destructive and constructive interference respectively, in the central peak and then is less so at either side.
The position of bright fringes in the screen where the pattern is formed can be calculated with
- m is the order number.
is the wavelength of the monochromatic light.
- L is the distance between the screen and the two slits.
- d is the distance between the slits.
- Part A: a) In the above equation for the position of bright fringes we can see that if the wavelength of the light
- Part B: b) In the above equation for the position of bright fringes we can see that if the spacing between the slits d is decreased the fringes are going to be wider apart. That means the fringe spacing Δy will increase.
- Part C: a) In the above equation we can see that if the distance to the screen L is decreased the fringes are going to be closer. That means the fringe spacing Δy will decrease.
- Part D: We are told that the central maximum is the fringe C that corresponds with m=0. That means that fringe E corresponds with the order number m=2 if we consider it to be the second maximum at the rigth of the central one. To calculate how much farther from the left slit than from the right slit is a dot located at the center of the fringe E in the screen we use the condition for constructive interference. That says that the path length difference Δr between rays coming from the left and right slit must be
We simply replace the values in that equation :
The dot in the center of fringe E is farther from the left slit than from the right slit.