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2 years ago

9

What is the definition of electrical energy?

1 answer:

kherson [118]2 years ago

7 0

Answer: Electrical energy is defined as an electric charge that lets work be accomplished. An example of electrical energy is power from a plug outlet. YourDictionary definition and usage example.

Explanation:

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2. What is the name of the following compound? *

alexgriva [62]

Answer: Cesium Nitrate

4 0

3 years ago

Which of the following is not an example of a chemical reaction? Rust Heat from Fire Photosynthesis Melting Ice

VARVARA [1.3K]

Melting ice. Hopefully this helps!

8 0

3 years ago

Read 2 more answers

Pls help this my final 20 points!!!! Be right

Anastaziya [24]

Answer:

I think it's B

Explanation:

I hope it helps

5 0

2 years ago

A mixture that has two or more substances that are spread out evenly is called _____

svlad2 [7]

Answer:

D

Explanation:

heterogeneous mixture you can see the different substances that go into it.

homogeneous mixture you can't see the difference, the mixture looks like one substance.

6 0

2 years ago

A 50.0 mL sample of a 1.00 M solution of CuSO4 is mixed with 50.0 mL of 2.00 M KOH in a calorimeter. The temperature of both sol

Reika [66]

Answer : The enthalpy change for the process is 52.5 kJ/mole.

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the solution

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the solution

$c_1$ = specific heat of calorimeter = $12.1J/^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_2$ = mass of water or solution = $Density\times Volume=1/mL\times 100.0mL=100.0g$

$\Delta T$ = change in temperature = $T_2-T_1=(26.3-20.2)^oC=6.1^oC$

Now put all the given values in the above formula, we get:

$q=[(12.1J/^oC\times 6.1^oC)+(100.0g\times 4.18J/g^oC\times 6.1^oC)]$

$q=2623.61J$

Now we have to calculate the enthalpy change for the process.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 2626.61 J

n = number of moles of copper sulfate used = $Concentration\times Volume=1M\times 0.050L=0.050mole$

$\Delta H=\frac{2623.61J}{0.050mole}=52472.2J/mole=52.5kJ/mole$

Therefore, the enthalpy change for the process is 52.5 kJ/mole.

8 0

3 years ago