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Digiron [165]
3 years ago
9

What is the definition of electrical energy?

Chemistry
1 answer:
kherson [118]3 years ago
7 0

Answer: Electrical energy is defined as an electric charge that lets work be accomplished. An example of electrical energy is power from a plug outlet. YourDictionary definition and usage example.

Explanation:

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An organism that regulates its body temperature using external heat sources is an example of
katovenus [111]
A cold-blooded animal. Cold-blooded animals can't generate heat themselves so they have to use external sources to keep them warm.
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4 years ago
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Starting with 1.5052g of BaCl2•2H2O and excessH2SO4, how many grams of BaSO4 can be formed?
muminat
1.5052g BaCl2.2H2O => 1.5052g / 274.25 g/mol = 0.0054884 mol
=> 0.0054884 mol Ba 
<span>This means that at most 0.0054884 mol BaSO4 can form since Ba is the limiting reagent. </span>
<span>0.0054884 mol BaSO4 => 0.0054884 mol * 233.39 g/mol = 1.2809 g BaSO4</span>
6 0
3 years ago
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What is the pH of a 0.40 M solution of C6H5COOH?
melomori [17]
What are the answer choices?
4 0
3 years ago
what is the specific heat of a substance if 1560 cal are required to raise the temperature of a 312-g sample by 15°C
jasenka [17]

Answer:

0.33 cal⋅g-1°C-1  

Explanation:

The amount of heat required is determined from the formula:

q= mcΔT

To see more:

https://api-project-1022638073839.appspot.com/questions/what-is-the-specific-heat-of-a-substance-if-1560-cal-are-required-to-raise-the-t#235434

7 0
3 years ago
In a Dam, If we doubled the depth of the dam the hydrostatic force will be ?
AnnZ [28]

Answer: Option (A) is the correct answer.

Explanation:

Force acting on a dam is as follows.

                  F = \frac{1}{2}\rho g\omega H^{2} .......... (1)

Now, when we double the depth then it means H is increasing 2 times and then the above relation will be as follows.

                F' = \frac{1}{2}\rho g\omega (2)^{2}

               F' = \frac{1}{2}\rho g\omega 4 ........... (2)

Now, dividing equation (1) by equation (2) as follows.

          \frac{F}{F'} = \frac{\frac{1}{2}\rho g\omega H^{2}}{\frac{1}{2}\rho g\omega 4}  

Cancelling the common terms we get the following.

                 \frac{F}{F'} = \frac{1}{4}    

                   4F = F'

Thus, we can conclude that if doubled the depth of the dam the hydrostatic force will be 4F.

4 0
3 years ago
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