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ElenaW [278]
3 years ago
11

10. calcium fluoride ca 11. sodium nitride 12. magnesium chloride In formulas

Chemistry
2 answers:
rosijanka [135]3 years ago
8 0

Answer:

10. CaF2

11. Na3N

12. MgCl2

Explanation:

ikadub [295]3 years ago
7 0

Answer:

10=CaF2

11=Na3N

12=MgCl2

Explanation:

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Elanso [62]

Answer:

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7 0
3 years ago
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Im literally failing some classes can some one help me with them
galben [10]

Answer:in can

Explanation:

5 0
3 years ago
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Perform the following for Part C of this lab:
kaheart [24]

Answer:

a. 0.0110 L

b. 0.0020 L

c. 0.011 mol

d. 5.5 M

e. 0.66 g

f. 33%

Explanation:

There is some info missing. I will use some values to show you the procedure and then you can replace them with your values.

<em>Titrant (NaOH) concentration: 1.0 M</em>

<em>Vinegar volume: 2.0 mL</em>

<em>Initial buret reading (initial NaOH volume): 0.1 mL</em>

<em>Final buret reading (final NaOH volume): 11.1 mL</em>

<em>a. Calculate the volume of NaOH that was added to the vinegar. Convert this volume to liters. Show your work.</em>

The volume of NaOH is the difference between the final and the initial buret reading.

11.1 mL - 0.1 mL = 11.0 mL × (1 L/1000 mL) = 0.0110 L

<em>b. Convert the measured volume of vinegar to liters. Show your work.</em>

2.0 mL × (1 L/1000 mL) = 0.0020 L

<em>c. Calculate the moles of NaOH using the volume and molarity of NaOH. Show your work. moles = molarity x volume</em>

moles = molarity × volume

moles = (1.0 mol/L) × 0.0110 L = 0.011 mol

<em>d. Since the reaction ratio is 1:1, the moles of acetic acid in the vinegar is equal to the moles of NaOH reacted during the titration. Calculate the molarity of the acetic acid in the vinegar. Show your work. molarity = moles / volume</em>

molarity = moles / volume

molarity = 0.011 mol/0.0020 L = 5.5 M

<em>e. Calculate the grams of acetic acid in the vinegar. Show your work. mass = moles x molar mass (g/mol)</em>

mass = moles × molar mass

mass = 0.011 mol × 60.05 g/mol = 0.66 g

<em>f. Assuming that the density of vinegar is very close to 1.0 g/mL, the 2.0 mL sample of vinegar used in the titration should weigh 2.0  g. Use this to calculate the mass % of acetic acid in the vinegar sample. mass % = (mass acetic acid / mass vinegar) * 100%</em>

mass % = (mass acetic acid / mass vinegar) * 100%

mass % = (0.66 g /2.0 g) * 100% = 33%

6 0
3 years ago
If 1.20 moles of copper react with mercuric nitrate how many moles of mercury form
Andrej [43]
Reaction of Copper with Mercuric Nitrate is as follow,

                       Cu  +  Hg(NO₃)₂    →    Cu(NO₃)₂  +  Hg

According to equation,

                            1 Mole of Cu reacts to form  =  1 Mole of Hg

So,

           1.20 Moles of Cu will react to produce  =  X Moles of Hg

Solving for X,

                                   X  =  (1.20 mol × 1 mol) ÷ 1 mol

                                   X  =  1.20 mol of Hg
Result:
          1.20 mole of Cu when reacted with mercuric nitrate produces 1.20 moles of Hg.
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4 years ago
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Mashutka [201]

<u>Answer: </u>The correct answer is Option A.

<u>Explanation:</u>

Fluorine is the 9th element in the periodic table which belongs to group 17 and period 2. It is a non-metal because it requires an electron to gain its stable electronic configuration.

The electronic configuration of this elements is: 1s^22s^22p^5

This element requires 1 electron to attain stable configuration. It is an insulator  and is not lustrous.

This element easily gains an electron and hence, is considered as a highly reactive non-metal.

Hence, the correct answer is Option A.

4 0
4 years ago
Read 2 more answers
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