The answer is a. a homogenous mixture
Answer:
<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
- First rewrite the sentence that defines the equation
Zinc (Zn) combines with hydrogen chloride (HCI) to form hydrogen gas(H2) and zinc chloride (ZnCl2).
<h3><u>Chemical</u><u> </u><u>Equation</u></h3>
![\sf Zinc+Hydrogen\:Chloride \longrightarrow Hydrogen\:gas+Zinc\:Chloride](https://tex.z-dn.net/?f=%5Csf%20Zinc%2BHydrogen%5C%3AChloride%20%5Clongrightarrow%20Hydrogen%5C%3Agas%2BZinc%5C%3AChloride)
![\sf Zn+HCL \longrightarrow H_2+ZnCl_2](https://tex.z-dn.net/?f=%5Csf%20Zn%2BHCL%20%5Clongrightarrow%20H_2%2BZnCl_2%20)
![\sf Zn+2HCL\longrightarrow H_2+ZnCl_2](https://tex.z-dn.net/?f=%5Csf%20Zn%2B2HCL%5Clongrightarrow%20H_2%2BZnCl_2%20)
<span>
</span><span>The answer is All of the above. The rearranged law incorporates Charles Law about the relationship between the volume and temperature of an ideal gas with Boyles law that stipulates the relationship between pressure and volume of an ideal gas. Avogadro principle strengthens on this formula by applying the standard of the number of atoms in a mole of gas.</span>(P1*V1)/T1 = (P2*V2)/T2
where:
<span><span><span>V is the volume</span>
</span></span><span><span>P is the pressure</span><span>
</span></span><span><span>T is the temperature measured in kelvin</span><span>
</span></span><span><span>k is a constant (with units of energy divided by temperature)</span></span>
Answer:
30.8 grams of magnesium hydroxide will form from this reaction, and magnesium nitrate is the limiting reagent.
Explanation:
The reaction that takes place is:
- 2NaOH + Mg(NO₃)₂ → 2NaNO₃ + Mg(OH)₂
Now we <u>convert the given masses of reactants to moles</u>, using their respective <em>molar masses</em>:
- 68.3 g NaOH ÷ 40 g/mol = 1.71 mol NaOH
- 78.3 g Mg(NO₃)₂ ÷ 148.3 g/mol = 0.528 mol Mg(NO₃)₂
0.528 moles of Mg(NO₃)₂ would react completely with (0.528 * 2) 1.056 moles of NaOH. There are more than enough NaOH moles, so NaOH is the reagent in excess and <em>Mg(NO₃)₂ is the limiting reagent.</em>
Now we <u>calculate how many Mg(OH)₂ are produced</u>, using the <em>moles of the limiting reagent</em>:
- 0.528 mol Mg(NO₃)₂ *
= 0.528 mol Mg(OH)₂
Finally we convert Mg(OH)₂ moles to grams:
- 0.528 mol Mg(OH)₂ * 58.32 g/mol = 30.8 g