Question

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Answer 1

Answer:

'See Explanation

Explanation:

Determine the [OH−] , pH, and pOH of a solution with a [H+] of 9.5×10−13 M at 25 °C.

Given [H⁺] = 9.5 x 10⁻¹³M => [H⁺][OH⁻] = 1.0 x 10⁻¹⁴ => [OH⁻] = 1.0 x 10⁻¹⁴/9.5 x 10⁻¹³ = 0.0105M

pH = -log[H⁺] = -log(9.5 x 10⁻¹³) = - (-1202) = 12.02.

pOH = -log[OH⁻] = -log(0.0105) = -(-1.98) = 1.98

Now you use the same sequence in the remaining problems.