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Vesna [10]
3 years ago
9

A student claims that when two bodies not initially in thermal equilibrium are placed in contact, the rise in temperature of the

cooler body must always be equal to the drop in temperature of the warmer body. Do you agree? Is there a principle of conservation of temperature or something like that?
Please answer in brief its for 10 marks​
Physics
1 answer:
zimovet [89]3 years ago
3 0

Answer:

Explanation:

No.

There is a difference between energy, called heat in this case, and temperature, which is a measure of the amount of heat contained in a material and is dependent on the material properties.

Temperature difference is what causes heat to move from one body to another.

Two objects at different temperatures placed in contact with one another will cause heat to move from the warmer body to the colder body until the temperature difference is eliminated.

The amount of heat leaving the warmer body will exactly equal the amount of heat absorbed by the cooler body. (assuming isolated system of two bodies) The temperature change within each of those bodies could be vastly different.

Example would be a 2 mm bead of molten lead dropped into a liter glass of tap water. The lead may cool several hundred °C as it solidifies while the water temperature would increase less than 1 °C

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A ball is thrown upward from the top of a building at an angle of 30.0° to the horizontal and with
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Answer:

See below

Explanation:

Vertical position = 45 +  20 sin (30) t  - 4.9 t^2

 when it hits ground this = 0

               0 = -4.9t^2 + 20 sin (30 ) t + 45

                0 = -4.9t^2 + 10 t +45 = 0     solve for t =4.22 sec

  max height is at  t= - b/2a = 10/9.8 =1.02

     use this value of 't' in the equation to calculate max height = 50.1 m

      it has  4.22 - 1.02 to free fall = 3.2 seconds free fall

           v = at = 9.81 * 3.2 = 31.39 m/s VERTICAL

      it will <u>also</u> still have horizontal velocity =  20 cos 30 = 17.32 m/s

        total velocity will be sqrt ( 31.39^2 + 17.32^2) = 35.85 m/s

Horizontal range = 20 cos 30  * t  =  20 *  cos 30  * 4.22 = 73.1 m

8 0
2 years ago
Einstein and Lorentz, being avid tennis players, play a fast-paced game on a court where they stand 20.0 m from each other. Bein
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Answer:

A) 185.6 J

B) 9.396 x 10^14 J

C) 4x10^7 m/s

D) 20 m

E) 9.09x10^-8 sec

F) 9.09x10^-8 sec

Explanation:

Detailed explanation and calculation is shown in the image below

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An electron is trapped between two large parallel charged plates of a capacitive system. The plates are separated by a distance
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Answer:

The electron will get at about 0.388 cm (about 4 mm) from the negative plate before stopping.

Explanation:

Recall that the Electric field is constant inside the parallel plates, and therefore the acceleration the electron feels is constant everywhere inside the parallel plates, so we can examine its motion using kinematics of a constantly accelerated particle. This constant acceleration is (based on Newton's 2nd Law:

F=m\,a\\q\,E=m\,a\\a=\frac{q\,E}{m}

and since the electric field E in between parallel plates separated a distance d and under a potential difference \Delta V, is given by:

E=\frac{\Delta\,V}{d}

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a=\frac{q\,\Delta V}{m\,d}

We want to find when the particle reaches velocity zero via kinematics:

v=v_0-a\,t\\0=v_0-a\,t\\t=v_0/a

We replace this time (t) in the kinematic equation for the particle displacement:

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0.005 - 0.00112 m = 0.00388 m [or 0.388 cm]

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