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Studentka2010 [4]
3 years ago
12

Assuming that all of the carbon dioxide ends up in the balloon, what will be the volume of the balloon at a temperature of 27 ∘C

and a pressure of 742 mmHg ?
Physics
2 answers:
Alexandra [31]3 years ago
6 0

Answer:

The volume of the balloon would be (580.12m) cm^3

Explanation:

From the ideal gas equation,

PV = nRT

P is pressure in the balloon = 742 mmHg = 742/760 = 0.976 atm

V is the volume of the balloon

n is the number of moles of carbon dioxide in the balloon. Let the mass of carbon dioxide be m.

n = mass/MW = m/44 = (0.023m) mol

R is gas constant = 82.057 cm^3.atm/mol.K

T is temperature of the balloon = 27 °C = 27 + 273 = 300 K

V = 0.023m × 82.057 × 300/0.976 = (580.12m) cm^3

horsena [70]3 years ago
3 0

Answer:

Explanation:

Given:

P = 742 mmHg

= 98925.2 Pa

T = 22 °C

= 295 K

R = 8.3145 J/mol.K

Molar mass of CO2, M = 12 + (16*2)

= 44 g/mol

Number of moles = mass/molar mass

= 28.8/44

= 0.655 mol.

Using ideal gas law,

PV = nRT

V = nRT/P

= 0.655 × 8.3145 × 295/98925.2

= 0.0162 m^3

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A wire is stretched between two posts. Another wire is stretched between two posts that are twice as far apart. The tension in t
Margarita [4]

Answer: 996m/s

Explanation:

Formula for calculating velocity of wave in a stretched string is

V = √T/M where;

V is the velocity of wave

T is tension

M is the mass per unit length of the wire(m/L)

Since the second wire is twice as far apart as the first, it will be L2 = 2L1

Let V1 and V2 be the speed of the shorter and longer wire respectively

V1 = √T/M1... 1

V2 = √T/M2... 2

Since V1 = 249m/s, M1 = m/L1 M2 = m/L2 = m/2L1

The equations will now become

249 = √T/(m/L1) ... 3

V2 = √T/(m/2L1)... 4

From 3,

249² = TL1/m...5

From 4,

V2²= 2TL1/m... 6

Dividing equation 5 by 6 we have;

249²/V2² = TL1/m×m/2TL1

{249/V2}² = 1/2

249/V2 = (1/2)²

249/V2 = 1/4

V2 = 249×4

V2 = 996m/s

Therefore the speed of the wave on the longer wire is 996m/s

3 0
3 years ago
a 0.40kg soccer ball approaches a player horizontally with a velocity of 18m/s north. the player strikes the ball and causes it
denis23 [38]
Impulse = Ft = (m)(delta v)
delta v = change in velocity = velocity final - velocity initial.
= -22m/s - +18m/s = -40m/s.
mdeltav = (0.40kg)(-40m/s) = -16kgm/s or -16Ns.

4 0
3 years ago
A 126- kg astronaut (including space suit) acquires a speed of 2.70 m/s by pushing off with her legs from a 1800-kg space capsul
jeka94

The change in the speed of the space capsule will be -0.189 m/s.

The average force exerted by each on the other will be 567 N.

The kinetic energy of each after the push for the astronaut and the capsule are 459.27 J and 32.14 J.

<h3>Given:</h3>

Mass of the astronaut, m_a = 126 kg

Speed he acquires, v_{a}  = 2.70 m/s

Mass of the space capsule, m_{c} = 1800kg

The initial momentum of the astronaut-capsule system is zero due to rest.

P_f = m_av_a + m_cv_c

P_I = 0

m_av_a + m_cv_c = 0

v_c =\frac{- m_a v_a}{m_c}}\\\\

   = \frac{126* 2.70}{1800}

   = - 0.189 m/s

Therefore,

According, to the impulse-momentum theorem;

FΔt = ΔP

ΔP = m Δv

ΔP = 126×2.70

    = 340.2 kgm/sec

t is time interval = 0.600s

F = ΔP/Δt

F = 340.2/0.600

  = 567 N

Therefore, the average force exerted by each on the other will be 567 N.

The Kinetic Energy of the astronaut;

K.E = \frac{1}{2} m v^2

     = \frac{1}{2} × 126 × (2.70) ^2

     = 459.27 J

The Kinetic Energy of the capsule;

K.E = \frac{1}{2} m v^2

     = \frac{1}{2}×1800×(0.189) ^2

     = 32.14 J

Therefore, the kinetic energy of each after the push for the astronaut and the capsule are 459.27 J and 32.14 J.

Learn more about kinetic energy here:

brainly.com/question/26520543

#SPJ1

3 0
1 year ago
The difference between the frequency fff and the frequency ωωomega is that fff is measured in cycles per second or hertz (abbrev
Kisachek [45]

Answer:

Radians

Explanation:

The angular speed is a measure of the rotation speed of a body. It is defined as the angle rotated by a unit of time. Thus, It refers to the angular displacement per unit time and is designated by the Greek letter \omega. Its unit in the International System is radian per second (rad / s).

6 0
3 years ago
The diagram shows the movement of air as a result of convection currents. At which point is the air at its highest density?
Gnesinka [82]

X

Hot air rises = it's less dense than cold air = falls

3 0
3 years ago
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