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Studentka2010 [4]
3 years ago
12

Assuming that all of the carbon dioxide ends up in the balloon, what will be the volume of the balloon at a temperature of 27 ∘C

and a pressure of 742 mmHg ?
Physics
2 answers:
Alexandra [31]3 years ago
6 0

Answer:

The volume of the balloon would be (580.12m) cm^3

Explanation:

From the ideal gas equation,

PV = nRT

P is pressure in the balloon = 742 mmHg = 742/760 = 0.976 atm

V is the volume of the balloon

n is the number of moles of carbon dioxide in the balloon. Let the mass of carbon dioxide be m.

n = mass/MW = m/44 = (0.023m) mol

R is gas constant = 82.057 cm^3.atm/mol.K

T is temperature of the balloon = 27 °C = 27 + 273 = 300 K

V = 0.023m × 82.057 × 300/0.976 = (580.12m) cm^3

horsena [70]3 years ago
3 0

Answer:

Explanation:

Given:

P = 742 mmHg

= 98925.2 Pa

T = 22 °C

= 295 K

R = 8.3145 J/mol.K

Molar mass of CO2, M = 12 + (16*2)

= 44 g/mol

Number of moles = mass/molar mass

= 28.8/44

= 0.655 mol.

Using ideal gas law,

PV = nRT

V = nRT/P

= 0.655 × 8.3145 × 295/98925.2

= 0.0162 m^3

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KiRa [710]

Answer:

Decreases the time period of revolution

Explanation:

The time period of Cygnus X-1 orbiting a massive star is 5.6 days.

The orbital velocity of a planet is given by the formula,

                                        v = √[GM/(R + h)]

In the case of rotational motion, v = (R +h)ω

                                         ω = √[GM/(R + h)] /(R +h)

Where 'ω' is the angular velocity of the planet

The time period of rotational motion is,

                                     T = 2π/ω

By substitution,

                                      <em>T = 2π(R +h)√[(R + h)/GM] </em>

Hence, from the above equation, if the mass of the star is greater, the gravitational force between them is greater. This would reduce the time period of revolution of the planet.

3 0
3 years ago
How does atomic bombs work?​
yarga [219]

Answer:

Nuclear fission produces the atomic bomb, a weapon of mass destruction that uses power released by the splitting of atomic nuclei. When a single free neutron strikes the nucleus of an atom of radioactive material like uranium or plutonium, it knocks two or three more neutrons free.

Explanation:

this chain reaction releases tremendous amount of energy

8 0
3 years ago
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A baseball is thrown straight up from a building that is 25 meters tall with an initial velocity v = 10 m/s. How fast is it goin
Yanka [14]

Answer:-24,5m/s

Explanation: what we have here is a UALM with these gravity as acceleration (-9.8 m/s^2). The initial position is 25 m and initial speed is 10m/s.

Speed and gravity are increasing in the opposite direction, speed upwards and gravity downwards, while the position is also upwards, depending on your reference system.

The first thing I need to know is the maximum high it will reach.

Hmax=- S(0)^2/2g=

S= speed.

0= initial

G= gravity

Hm= 100/19,6= 5.1 m

So, the ball will go 5,1 m higher than the initial position, and from there it will fall free.

Then, I need to know how long it takes to fall. For that we use UALM equation:

X(t)= X(0) + S(0)*t + (A*t^2)/2.

X: position

S: speed

A: acceleration

T:time

0: initial

0 = 25m +10*t -(9.8 * t^2)/2

Solving the quadratic equation we get

T= 3,5 sec. ( Negative value for time is impossible)

So now we know that the ball to go up and then fall needs 3,5 sec.

Let's see how long it takes to go up:

30,1=25+10*t-4,9*t^2

0=-5,1+10*t-4,9*t^2

T= 1 sec. So it will take 1 sec to the ball to reach the maximum high and 0=speed and then it'll fall during the resting 2,5 sec

Finally, to know the speed just before it touches the ground, we use the following formula:

A= (St-S0)/t

-9.8m/s^2 = (St- 0m/s)/ 2,5s

-24,5 m/s= St

-24,5 m/s is the speed at 3,5 sec, which is the time just before falling

3 0
3 years ago
Use the diagram to explain how convection occurs inside the earth. What could convection cause to occur on earths surface
liubo4ka [24]

Answer:

mantle convection is the very slow creeping motion of earths solid silicate mantle caused by convection currents carrying heat from the interior to the planet's surface.

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If you walk 30 meters forwards, and then turn around and walk 25 meters backwards, what is the distance that you walked? What di
xeze [42]

Given :

Walk in forward direction is 30 m .

Walk in backward direction is 25 m .

To Find :

The distance and displacement .

Solution :

We know , distance is total distance covered and displacement is distance between final and initial position .

So , distance travelled is :

D = 30 + 25 m = 55 m .

Now , we first move 30 m in forward direction and then 25 m in backward direction .

So , displacement is :

D = 30 - 25 m = 5 m .

Therefore , distance and displacement covered is 55 m and 5 m respectively .

Hence , this is the required solution .

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