Https://us-static.z-dn.net/files/d49/33d4ec86853ef95e6f6c14242c663be4.png
The coordination compounds' names or formulas, the oxidation state of each metal ion, and the electronic configuration of the each metal ion.
1. [V(OH2)6](NO3)3 - Vanadium(V) Oxidation State: +5 Electronic Configuration: [Ar] 3d3 4s2
2. (NH4)2[CoCl4] - Cobalt(II) Oxidation State: +2 Electronic Configuration: [Ar] 3d7 4s2
3. [Co(py)4]Br2 - Cobalt(III) Oxidation State: +3 Electronic Configuration: [Ar] 3d6 4s2
4. K4[Mn(CN)6] - Manganese(II) Oxidation State: +2 Electronic Configuration: [Ar] 3d5 4s2
5. [Co(P(CH3)3)4]2(SO4) - Cobalt(III) Oxidation State: +3 Electronic Configuration: [Ar] 3d6 4s2
6. Ni(NH3)4Cl2 - Nickel(II) Oxidation State: +2 Electronic Configuration: [Ar] 3d8 4s2
7. [CrCl2(OH2)4]+ - Chromium(III) Oxidation State: +3 Electronic Configuration: [Ar] 3d5 4s1
What is Electronic Configuration?
The arrangement of an atom's or molecule's (or other physical structure's) electrons in their atomic or molecular orbitals is known as the electron configuration in atomic physics as well as quantum chemistry. For instance, the neon atom's electron configuration is 1s2 2s2 2p6, which means that 1, 2 and 6 electrons, respectively, are present in each of the 1s, 2s, and 2p subshells. According to electronic configurations, each electron moves independently within an orbital while being surrounded by an average field produced by all other orbitals. Slater determinants as well as configuration state functions are used to mathematically describe configurations.
To learn more about Electronic Configuration
brainly.com/question/21977349
#SPJ4
They are the same because the definition of a mole is 6.022 x 10^23 molecules or atoms based on whether it is a molecule or element. so there are 6.022 x 10^23 atoms of argon in one mole of argon and 6.022 x 10^23 molecules of ammonia in one mole of ammonia
A chemical energy like burning
Answer:
C1 * V1 = C2 * V2
Explanation:
Where ‘C’ and ‘V’ refer to concentration and volume, ‘1’ and ‘2’ to solution 1 and 2 respectively. So, if ‘1’ refers to the HCl solution, we want to solve this equation for C1.
V1 = (C2*V2)/C1 = (0.4 * 50)/40 = 0.5 M