Answer:
182 to 3 s.f
Explanation:
Workdone for an adiabatic process is given as
W = K(V₂¹⁻ʸ - V₁¹⁻ʸ)/(1 - γ)
where γ = ratio of specific heats. For carbon dioxide, γ = 1.28
For an adiabatic process
P₁V₁ʸ = P₂V₂ʸ = K
K = P₁V₁ʸ
We need to calculate the P₁ using ideal gas equation
P₁V₁ = mRT₁
P₁ = (mRT₁/V₁)
m = 2.80 g = 0.0028 kg
R = 188.92 J/kg.K
T₁ = 27°C = 300 K
V₁ = 500 cm³ = 0.0005 m³
P₁ = (0.0028)(188.92)(300)/0.0005
P₁ = 317385.6 Pa
K = P₁V₁¹•²⁸ = (317385.6)(0.0005¹•²⁸) = 18.89
W = K(V₂¹⁻ʸ - V₁¹⁻ʸ)/(1 - γ)
V₁ = 0.0005 m³
V₂ = 2.10 dm³ = 0.002 m³
1 - γ = 1 - 1.28 = - 0.28
W =
18.89 [(0.002)⁻⁰•²⁸ - (0.0005)⁻⁰•²⁸]/(-0.28)
W = -67.47 (5.698 - 8.4)
W = 182.3 = 182 to 3 s.f
Florine is special becaus Florine is at the highest value of electronegative value with 4.0
Slightly downstream for the shortest possible time
Particle arrangement and movement
⇒ In terms of relative energy, gas particles have the most energy, solid particles have the least energy and liquid particles are somewhere in between. (All compared at the same temperature.)
<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>
Let: m=1.50Kg, r=0.094m, h=2.50m, teta=86.4 and g=9.81m/s^2. The moment of inertia of a sphere is I=(2/5)*m*r^2, vi=0m/s, hf=0m, and the condition that a spherical object is rolling whitout slipping is w=V/r. So, by conservation of energy: mgh= (1/2)*((m*Vf^2)+(I*wf)). substituting, and clearing, Vf=((10/7)*g*h)^(1/2)=((10/7)*(9.81)*(2.50))^(1/2)=5.9190 m/s
