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stepan [7]
3 years ago
12

An object of mass m is oscillating back and forth in simple harmonic motion. The maximum origin, x = 0, and moving in the x dire

ction. Find the following in terms of m, T, and A:(a)The equation of motion of the object, (b)The maximum speed of the object (c)The maximum distance from equilibrium is A, and the period of oscillation is T. At t = 0 the object is at the acceleration of the object.(d)The total energy of the object.​
Physics
1 answer:
cluponka [151]3 years ago
5 0

Answer:

x = A sin ω  t      equation of motion

max speed = A ω

max distance (max value of x) = A

max KE = 1/2 m V^2 = 1/2 m A^2 ω^2

f (frequency) =  ω / 2 π = 1 / T     or T =  2 π /  ω

ω = 2 π / T     substitute for ω to put in terms of T

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I need help with this.
madreJ [45]

Answer:

A.The new discovery might cause the theory to be dismissed since it contradicts it.

Or

D.The new discovery might further deny the theory since it presents evidence that contradicts it.

Itl be hard for them to decide you know, since this bigbang theory by darwin is widespread and cant be easily opposed..

_Askmeanything2♡

4 0
3 years ago
Kathy had a heavy metal ball and Rich had a light wooden ball they drop the balls from the same height. they were surprised to d
Colt1911 [192]

Answer: I scored a 9/10

Explanation:

I agree with Kathy gravity must be acting the same on both balls just because one ball is heavier doesn’t mean they will hit different times if the wooden ball was drop closer to the ground then the wooden ball would hit the ground first

3 0
3 years ago
By what factor is the intensity of sound at a rock concert louder than that of a whisper when the two intensity levels are 120 d
lyudmila [28]

Answer:

d) 7.94\times 10^{9}

Explanation:

β₁ = sound level of sound at rock concert = 120 dB

β₂ = sound level of sound due to whisper = 21 dB

I₁ = Intensity of sound at rock concert

I₂ = Intensity of sound due to whisper

sound level of sound at rock concert is given as

\beta _{1} = 10 log\left ( \frac{I_{1}}{10^{-12}} \right )

120 = 10 log\left ( \frac{I_{1}}{10^{-12}} \right )

12 = log\left ( \frac{I_{1}}{10^{-12}} \right )               Eq-1

sound level due to whisper is given as

\beta _{2} = 10 log\left ( \frac{I_{2}}{10^{-12}} \right )

21 = 10 log\left ( \frac{I_{2}}{10^{-12}} \right )

2.1 = log\left ( \frac{I_{2}}{10^{-12}} \right )                          Eq-2

subtracting Eq-2 from Eq-1

12 - 2.1 = log\left ( \frac{I_{1}}{10^{-12}} \right ) - log\left ( \frac{I_{2}}{10^{-12}} \right )

9.9 = log\left ( \frac{I_{1}}{I_{2}} \right )

\left ( \frac{I_{1}}{I_{2}} \right ) = 7.94\times 10^{9}

6 0
3 years ago
Name one property of each planet.​
Archy [21]

Answer:

1)every planet move in elliptical path.

3 0
4 years ago
Help please! Test tomorrow!
dlinn [17]

Earth distance to the Sun is about 40 times the Moon's distance from earth.

<u>Explanation:</u>

  • The Earth's distance from the Sun is about 93 million miles. When it expressed in Km, it is 150 million Km.
  • The Moon's distance from Earth is 238,855 miles. When it is 40 times then it will approximately equal to 93 million miles.
  • The Sun's distance from Venus is 67.237 million miles. The Sun's distance from mercury is 35.832 million miles.
7 0
4 years ago
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