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olchik [2.2K]
3 years ago
8

Which statement best describes how light waves travel in a uniform medium. A. in straight lines. . B. in extending circles. . C.

in bent lines. . D. in shrinking ripples
Physics
2 answers:
Tanya [424]3 years ago
6 0
Light waves travel in straight lines when they are travelling in a uniform medium. This is because the waves are travelling at the same speed.
g100num [7]3 years ago
6 0

The answer is a. Straight lines

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A mouse ran 100 centimeters in
olga_2 [115]

Answer:

his speed is 5cm a second

7 0
2 years ago
Read 2 more answers
Calculate the induced electric field (in V/m) in a 40-turn coil with a diameter of 11 cm that is placed in a spatially uniform m
Naddik [55]

Answer:

Explanation:

Given that,

Number of turn N = 40

Diameter of the coil d= 11cm = 0.11m

Then, radius = d/2 = 0.11/2 =0.055m

r = 0.055m

Then, the area is given as

A =πr²

A = π × 0.055²

A = 9.503 × 10^-3 m²

Magnetic Field B = 0.35T

Magnetic field reduce to zero in 0.1s, t = 0.1s

so we want to find induce electric field. To find the electric field,(E) we need to find the electric potential (V).

E.M.F is given as

ε = —N • dΦ/dt

Where magnetic flux is given as

Φ = BA

Then, ε = —N • dΦ/dt

ε = —N • dBA/dt

ε = —NBA/t

Then, its magnitude is

ε = NBA/t

Inserting the values of N, B, A and t

ε = 40×0.35×9.503×10^-3/0.1

ε = 1.33 V

Then, using the relationship between Electric field and electric potential

V = Ed

ε = E•d

E = ε/d

E = 1.33/0.11

E = 12.09 V/m

7 0
3 years ago
A car has a mass of 8000 kg and a kinetic energy of 24,000 J. What is its<br> speed?
Liula [17]

Answer:

30 mph

Explanation:

8 0
2 years ago
Help!! Please!!
sattari [20]
<span> the answer is 1,500 & 1,700


</span>
6 0
3 years ago
The Hubble Space Telescope was released from the Space Shuttle, which was in a circular orbit at 400km earth altitude. The relat
snow_lady [41]

Answer:

d = (75 i ^ + 93 j ^ + 27 k ^) m ,  d2 = (900 i ^ + 1116 j ^ + 324 k ^) m

Explanation:

The two objects are in circular orbit together, therefore with the same angular velocity, after the launch they move with the relative velocity, so we can use the kinematic relation

       

         v = d / t

         d = v t

Reduce time to units SI

         t = 5 min (60 s / 1 min) = 300 s

X axis

         x = vₓ t

         x = 0.25 300

         x = 75 m

Y axis  

        y = v_{y} t

        y = 0.31 300

       y = 93 m

Z axis

        z=  v_{z} t

        z = 0.09 300

       z = 27 m

       d = (75 i ^ + 93 j ^ + 27 k ^) m

For the time of 1 h

       t2 = 1 h (3600s / 1 h) = 3600

       x2 = 900 m

       y2 = 1116 m

       z2 = 324 m

      d2 = (900 i ^ + 1116 j ^ + 324 k ^) m

5 0
3 years ago
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