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Nutka1998 [239]
3 years ago
8

How many days of a diet of 1910 large calories are equivalent to the gravitational energy change from sea level to the top of Mo

unt Everest, 8848 m above sea level? Assume your mass is 53 kg. (The body is not anywhere near 100% efficient in converting chemical energy into change in altitude. Also note that this is in addition to your basal metabolism.)
Physics
1 answer:
andreyandreev [35.5K]3 years ago
3 0

Answer:

0.58 days is needed

Explanation:

Gravitational energy change from a height change equal to 8848 m for a mass of 53 kg is:

m*g*h = 53*9.81*8848 = 4600340.64 J = 4600.34 kJ

4.184 kJ are equivalent to 1 kcal, then:

4.184 kJ / 4600.34 kJ = 1 kcal / x kcal

x = 4600.34/4.184

x = 1099.5 kcal or large calories

The diet is 1910 kcal/day, then you need 1099.5/1910 = 0.58 days

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If 50 km thick crust having an average density of 3.0 g/cm3 has a surface elevation of 2.5 km above sea level, what would you pr
RUDIKE [14]

Answer:

To calculate the predicted surface elevation of a 50km thick crust above a surface of 2.5km we are given a density of 3 gram per centimeter cube.

The displacement of the material will be calculated by subtracting the surface elevation of 2.5 km from the 50 km thick crust. Therefore 50-25= 47.5 km.

Thus let the density of the material be Pm

50*3= 47.5*Pm

Therefore: Pm= (50*3)/47.5= 3.16gram per centimeter cube

Thus with an average density of 2.8gram per centimeter cube

50*2.8= (50-x)*3.16

(50-x)= (50*2.8)/3.16

50-x=44.3

x=50-44.3= 5.7

Explanation:

To calculate the predicted surface elevation of a 50km thick crust above a surface of 2.5km we are given a density of 3 gram per centimeter cube.

The displacement of the material will be calculated by subtracting the surface elevation of 2.5 km from the 50 km thick crust. Therefore 50-25= 47.5 km.

Thus let the density of the material be Pm

50*3= 47.5*Pm

Therefore: Pm= (50*3)/47.5= 3.16gram per centimeter cube

Thus with an average density of 2.8gram per centimeter cube

50*2.8= (50-x)*3.16

(50-x)= (50*2.8)/3.16

50-x=44.3

x=50-44.3= 5.7

5 0
3 years ago
Which property of gold allows it to be used this way?
densk [106]

the electric conductivity of gold is very high

3 0
3 years ago
What is the formula to find initial velocity?​
Inga [223]

Answer:

s = ut + 1/2at^2

Explanation:

s= distance

u= initial velocity

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7 0
3 years ago
Nathan is walking to the store and sees a snake slithering across the sidewalk. He jumps over it with an initial vertical veloci
Travka [436]

Answer:

0.62\:\mathrm{s}

Explanation:

Since the universal SI unit for velocity is meters/second, let's convert ft/s to m/s:

10\:\mathrm{ft/s}=3.048\:\mathrm{m/s}

We can use the following kinematics equation to solve this question:

v_f=v_i+at

What we know:

  • The initial velocity, v_i, is 3.048\:\mathrm{m/s}
  • (physics concept) The final velocity must be equal in magnitude but opposite in direction to the initial velocity (v_f=-3.048\:\mathrm{m/s})
  • Acceleration, a, is acceleration due to gravity at about 9.8\:\mathrm{m/s}

Solving for t:

-3.048=3.048+(-9.8t),\\-6.096=-9.8t,\\t=\frac{-6.096}{-9.8}\approx \boxed{0.62\:\mathrm{s}}

8 0
3 years ago
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