A 3.50 cm tall object is held 24.8 cm from a lens of focal length 16.0 cm. What is the image height?
1 answer:
Answer:
<h2>
6.36 cm </h2>
Explanation:
Using the formula to first get the image distance
1/f = 1/u+1/v
f = focal length of the lens
u = object distance
v = image distance
Given f = 16.0 cm, u = 24.8 cm
1/v = 1/16 - 1/24.8
1/v = 0.0625-0.04032
1/v = 0.02218
v = 1/0.02218
v = 45.09 cm
To get the image height, we will us the magnification formula.
Mag = v/u = Hi/H
Hi = image height = ?
H = object height = 3.50 cm
45.09/24.8 = Hi/3.50
Hi = (45.09*3.50)/24.8
Hi = 6.36 cm
The image height is 6.36 cm
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Hey there!So we know that m*v=P. And in this question m=30 v=5 m/s P = 30*5 Kgm/s P = 150 Kgm/s So, your final answer is 150 Kg.m/s
