Answer: Plant A
Explanation: The control group is participants who do not receive the experimental treatment.
Answer:
lowest frequency = 535.93 Hz
distance between adjacent anti nodes is 4.25 cm
Explanation:
given data
length L = 32 cm = 0.32 m
to find out
frequency and distance between adjacent anti nodes
solution
we consider here speed of sound through air at room temperature 20 degree is approximately v = 343 m/s
so
lowest frequency will be =
..............1
put here value in equation 1
lowest frequency will be =
lowest frequency = 535.93 Hz
and
we have given highest frequency f = 4000Hz
so
wavelength =
..............2
put here value
wavelength =
wavelength = 0.08575 m
so distance =
..............3
distance =
distance = 0.0425 m
so distance between adjacent anti nodes is 4.25 cm
Answer: (Sorry, but I don't know how to calculate mass)
1. 15 N
2. 0.4921
(feet per second squared)
4. 150 N
5. 8.202 feet per second squared
<span>All of the waves in the electromagnetic spectrum are transverse waves.</span>