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<span>Exactly 33/532, or about 6.2%
This is a conditional probability, So what we're looking for is the probability of 2 gumballs being selected both being red. So let's pick the first gumball.
There is a total of 50+150+100+100 = 400 gumballs in the machine. Of them, 100 of the gumballs are red. So there's a 100/400 = 1/4 probability of the 1st gumball selected being red.
Now there's only 399 gumballs in the machine and the probability of selecting another red one is 99/399 = 33/133.
So the combined probability of both of the 1st 2 gumballs being red is
1/4 * 33/133 = 33/532, or about 0.062030075 = 6.2%</span>
Answer:
3
Step-by-step explanation:
It's decreasing by 3 each time, so the next number in the sequence would be 6 - 3, which is 3.
Answer:
1058.4 in^2
Step-by-step explanation:
Find the surface areas of the rectangular prism and the triangular prisms separately.
Triangular: S = (1/2)lP+B, where l is slant height, P perimeter, and B base area.
14(4)= 56 perimeter of base
13 slant height
B = 14x14 = 196
put together:
S = (1/2)(13 x 56) + 196
S = 560 in^2
Now the rectangular prism
S = 2lw + 2lh + 2wh, where l is length, h height, w width. (delete the first 2lw since they share one side/they're combined shapes.
S = 2(14x8.9) + 2(14x8.9)
S = 498.4 in^2
Add them together: 498.4 + 560 = 1058.4 in^2
Answer:
72-12k plz mark brainlest
Step-by-step explanation: