I can help you with 5. 5 is a displacement-time graph.
At A it is moving in a positive direction and speed is constant.
At B it is stationary or at rest.
At C, movement is negative and it is decreasing or decelerating
At D, it’s a general downwards movement in the negative direction that can be described as overall constant
Answer:
Avogadro's law.
Explanation:
Avogadro’s law states that, equal volumes of all gases at the same temperature and pressure contain the same number of molecules.
Mathematically,
V n
V = Kn where V = volume in cm3, dm3, ml or L; n = number of moles of gas;
K = mathematical constant.
The ideal gas equation is a combination of Boyle's law, Charles' law and Avogadro’s law.
V 1/P at constant temperature (Boyle’s law)
V T at constant pressure ( Charles’law)
V n at constant temperature and pressure ( Avogadro’s law )
Combining the equations yields,
V nT/P
Introducing a constant,
V = nRT/P
PV = nRT
Where P = pressure in atm, Pa, torr, mmHg or Nm-2; V = volume in cm3, dm3, ml or L; T = temperature in Kelvin; n = number of moles of gas in mol; R = molar gas constant = 0.082 dm3atmK-1mol-1
During its lifepsan, the sun's core would keep contracting and heating up.
The temperature will keep increasing to the point where the temperature outside the core will get to hydrogen fusion temperatures.
The sun will grow in surface and eventually became the Red Giant
<span>Then, since the peak wavelength of the star Beta is 200nm, use Wein law and round 200 to the nearest WHOLE NUMBER. Hope that helps. </span>
Answer:
d) 1.2 mT
Explanation:
Here we want to find the magnitude of the magnetic field at a distance of 2.5 mm from the axis of the coaxial cable.
First of all, we observe that:
- The internal cylindrical conductor of radius 2 mm can be treated as a conductive wire placed at the axis of the cable, since here we are analyzing the field outside the radius of the conductor. The current flowing in this conductor is
I = 15 A
- The external conductor, of radius between 3 mm and 3.5 mm, does not contribute to the field at r = 2.5 mm, since 2.5 mm is situated before the inner shell of the conductor (at 3 mm).
Therefore, the net magnetic field is just given by the internal conductor. The magnetic field produced by a wire is given by
where
is the vacuum permeability
I = 15 A is the current in the conductor
r = 2.5 mm = 0.0025 m is the distance from the axis at which we want to calculate the field
Substituting, we find:
