Ask question

Ask question

All categories

3 years ago

6

Every 6 seconds a pendulum completes one cycle.

2 answers:

Pavel [41]3 years ago

7 0

The period is 2.4 seconds and the frequency is I believe 1/6 I'm not entirely sure since I don't think this question has enough information.

Basile [38]3 years ago

4 0

The period is the time it takes any repeating process
to complete one cycle. You just told us what it is for the
pendulum . . . 6 seconds.

The frequency is the reciprocal of the period. For the pendulum,
that's

1 / (6 sec) = (1/6) per second = 1/6 Hertz .

You might be interested in

What is 62.125 kg rounded to two significant figures?

Mamont248 [21]

<em> </em><em> </em><em>62.125</em>

<em>=</em><em> </em><em>62.12</em>

<em>THANK</em><em> </em><em>you</em><em> </em>

6 0

3 years ago

1. What do you notice from the picture?<br>2. Did anyone get the correct answer?

Fudgin [204]

Answer:

1. I notice nothing because is no picture it probably didnt work

2. idk

6 0

3 years ago

The theory that the Earth's crust and part of the upper mantle are broken into sections that move on a fluid layer of the mantle

VMariaS [17]

I most sure about c but could be wrong

6 0

3 years ago

What sort of fitness component would dance be<br> categorized under

zalisa [80]

Answer:

aerobic fitness

Explanation:

i just looked it up lol

6 0

2 years ago

The ballistic pendulum is a device used to measure the speed of a projectile such as a bullet. The projectile of mass m is fired

My name is Ann [436]

Answer:

Relation between initial speed of bullet and height h is given as

$v = \frac{m + M}{m}\sqrt{2gh}$

Explanation:

As we know that system of block and bullet swings up to height h after collision

So we have

$(m + M)gh = \frac{1}{2}(m + M)v_1^2$

so we have

$v_1 = \sqrt{2gh}$

so speed of the block + bullet just after the impact is given by above equation

Now we also know that there is no force on the system of bullet + block in the direction of motion

So we can use momentum conservation

$mv = (m + M)v_1$

now we have

$v = \frac{m + M}{m}\sqrt{2gh}$

5 0

3 years ago