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Katen [24]
2 years ago
11

Calculate the temperature in k of 3.05 moles of gas occupying 3.70 L at 4.12 atm

Chemistry
1 answer:
Gnoma [55]2 years ago
6 0

Answer:

{ \bf{PV = nRT}} \\ { \tt{(4.12 \times 3700) = 3.05 \times 0.083 \times T }} \\ { \tt{15244 = 0.25315 \: T}} \\ { \tt{T = 6.02 \times  {10}^{4} \: kelvin }}

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If 0.583 g of ammonia (NH3) is dissolved to make 250 mL of solution, what is the molarity?
Misha Larkins [42]

Answer:

0.137 M NH3

Explanation:

First divide the mass of NH3 by the molar mass of NH3, and then divide by the volume to get molarity.

0.583 g / 17.031 g/mol = 0.0342 mol NH3

0.0342 mol NH3 / 0.250 L = 0.137 M NH3

7 0
3 years ago
100 POINTS PLEASE HELP (PHOTOS INCLUDED)
pshichka [43]

Answer:

Explanation:

3.

Knowns: 100mL of solution; concentration of 0.7M

Unknown: number of moles

Equation: number of moles = volume * concentration

Plug and Chug: number of moles = 100/1000 * 0.7 = 0.07 mole

Final Answer: 0.07mole

2.

Knowns: 5.50L of solution; concentration of 0.400M

Unknown: number of moles

Equation: number of moles = volume * concentration

Plug and Chug: number of moles = 5.5 * 0.4 = 2.20 mole

Final Answer: 2.20 mole

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2 years ago
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3 years ago
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1. You are pushing a heavy shopping cart full of water bottles with a constant force. The shopping cart has
jarptica [38.1K]

Answer:

F = 50 N

Explanation:

Given data:

Mass of car = 250 Kg

Acceleration of car = 0.20 m/s²

Force required = ?

Solution:

Formula:

F = m×a

F = applied  force

m = mass

a = acceleration

Now we will put the values in formula.

F =  250 Kg × 0.20 m/s²

F = 50 Kg.m/s²

Kg.m/s² = N

F = 50 N

3 0
2 years ago
A fuel tank holds 22.3 gallons of gasoline. If the density is 0.8206 g/mL, what is the mass in kilograms of gasoline in a full t
7nadin3 [17]

Answer:

m=69.3kg

Explanation:

Hello!

In this case, since the density is computed by dividing the mass of the substance by its occupied volume (d=m/V), we first need to realize that 0.8206 g/mL is the same to 0.8206 kg/L, which means we first need to compute the volume in L:

V=22.3gal*\frac{3.78541L}{1gal}=84.415L

Then, solving for the mass in d=m/V, we get m=d*V and therefore the mass of gasoline in that full tank turns out:

m=0.8206g/L*84.415L\\\\m=69.3kg

Best regards!

8 0
3 years ago
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