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Katen [24]
2 years ago
11

Calculate the temperature in k of 3.05 moles of gas occupying 3.70 L at 4.12 atm

Chemistry
1 answer:
Gnoma [55]2 years ago
6 0

Answer:

{ \bf{PV = nRT}} \\ { \tt{(4.12 \times 3700) = 3.05 \times 0.083 \times T }} \\ { \tt{15244 = 0.25315 \: T}} \\ { \tt{T = 6.02 \times  {10}^{4} \: kelvin }}

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Answer:

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ppm (parts per million) concentration is defined as the mass (in milligrams) of a substance dissolved in one liter of solution.

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Now we devise the following reasoning:

if         12.41 g of MgBr₂ are dissolved in 2.55 L of water

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