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Katen [24]
3 years ago
11

Calculate the temperature in k of 3.05 moles of gas occupying 3.70 L at 4.12 atm

Chemistry
1 answer:
Gnoma [55]3 years ago
6 0

Answer:

{ \bf{PV = nRT}} \\ { \tt{(4.12 \times 3700) = 3.05 \times 0.083 \times T }} \\ { \tt{15244 = 0.25315 \: T}} \\ { \tt{T = 6.02 \times  {10}^{4} \: kelvin }}

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Naya [18.7K]

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48×5/9

240/9

26.66°C

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58×5/9

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10 (212-32)5/9

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8 0
3 years ago
Which direction will the following reaction (in a 5.0 L flask) proceed if the pressure of CO_2(g) is 1.0 atm? CaCO_3(s) rightarr
storchak [24]

Answer:

d. To the left because Q > K_p

Explanation:

Hello,

In this case, for the given reaction:

CaCO_3(s) \rightarrow CaO(s) + CO_2(g)

The pressure-based equilibrium expression is:

Kp=p_{CO_2}

In such a way, since Kp is given we rather compute the reaction quotient at the specificed pressure of carbon dioxide as shown below:

Q=p_{CO2}=1.0

Therefore, since Q>Kp we can see that there are more products than reactants, which means that the reaction must shift leftwards towards the reactants in order to reestablish equilibrium, thus, answer is d. To the left because Q > Kp.

Regards.

6 0
3 years ago
How does your Skeletal and Muscular Systems work together?
elena-s [515]

Answer:

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Explanation:

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3 0
3 years ago
Read 2 more answers
For the reaction, Cl2 + 2KBr --> 2KCl + Br2, how many moles of potassium chloride, KCl, are produced from 102g of potassium b
Sedaia [141]

Solution :

From the balanced chemical equation, we can say that 1 moles of KBr will produce 1 moles of KCl .

Moles of KBr in 102 g of potassium bromide.

n = 102/119.002

n = 0.86 mole.

So, number of miles of KCl produced are also 0.86 mole.

Mass of KCl produced :

m = 0.86 \times Molar \  mass \ of \  KCl\\\\m = 0.86 \times 74.5 \ gram \\\\m = 64.07\  gram

Hence, this is the required solution.

5 0
3 years ago
What is the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M EDTA solution. The molar mass of EDTA is 374 g/mol
statuscvo [17]

Answer:

58.92 g EDTA

Explanation:

315.1 mL = .3151 L    

M = Moles / Liter

.3151 L  x <u>0.5 mol EDTA</u>  x  <u>374 g EDTA</u>  =  58.92 g EDTA

                1 L EDTA             1 mol EDTA

4 0
2 years ago
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