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Julli [10]
2 years ago
11

A 50.0 g golf ball is struck by a driver whose head has a mass of 500.0 kg. The final speed of the golf ball after leaving the t

ee is 45.0 m/s. Find the final momentum of the golf ball.
A)2.5 kg·m/s
B)5.0 kg·m/s
C)7.5 kg·m/s
D)10.0 kg·m/s
Physics
1 answer:
Savatey [412]2 years ago
8 0

<h2>A. 2.5 kg.m/s</h2>

this is my answer sure po ako n tama iyan

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G
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6 0
3 years ago
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Turn the ignition switch to start and release the key immediately or you could destroy the______________.
vredina [299]

Starter

Explanation:

Turn the ignition switch to start and release the key immediately or you could destroy the starter.

The car starter is used to cause ignition in the internal combustion engine in order to fire the piston and cause mechanical motion. The starter is used to start the cyclic process of the internal combustion engine.

  • Once the engine starts by igniting the starter, it is best to release it.
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5 0
3 years ago
(6) A 75 kg human total footprint area is 0.05 m2 when wearing winter boots. Suppose that you want to walk on snow that can at m
fredd [130]

Answer:

0.25m²

Explanation:

We know that the summation of forces in the vertical direction is zero

So

PA-mg=0

A=mg/p

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3 0
3 years ago
A supersonic nozzle is also a convergent–divergent duct, which is fed by a large reservoir at the inlet to the nozzle. In the re
Lady_Fox [76]

Answer:

155.38424 K

2.2721 kg/m³

Explanation:

P_1 = Pressure at reservoir = 10 atm

T_1 = Temperature at reservoir = 300 K

P_2 = Pressure at exit = 1 atm

T_2 = Temperature at exit

R_s = Mass-specific gas constant = 287 J/kgK

\gamma = Specific heat ratio = 1.4 for air

For isentropic flow

\frac{T_2}{T_1}=\frac{P_2}{P_1}^{\frac{\gamma-1}{\gamma}}\\\Rightarrow T_2=T_1\times \frac{P_2}{P_1}^{\frac{\gamma-1}{\gamma}}\\\Rightarrow T_2=00\times \left(\frac{1}{10}\right)^{\frac{1.4-1}{1.4}}\\\Rightarrow T_2=155.38424\ K

The temperature of the flow at the exit is 155.38424 K

From the ideal equation density is given by

\rho_2=\frac{P_2}{R_sT_2}\\\Rightarrow \rho=\frac{1\times 101325}{287\times 155.38424}\\\Rightarrow \rho=2.2721\ kg/m^3

The density of the flow at the exit is 2.2721 kg/m³

4 0
3 years ago
The charge of most alkaline earth metals.​
frutty [35]

Answer:

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Explanation:  The alkaline earth metals have two valence electrons in their highest-energy orbitals (ns2). They are smaller than the alkali metals of the same period, and therefore have higher ionization energies. In most cases, the alkaline earth metals are ionized to form a 2+ charge

Hope this helps, have a great day :)

7 0
2 years ago
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