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2 years ago

8

A 330.-ohm resistor is connected to a 5.00-volt battery. What is the current through the resistor?

2 answers:

Gelneren [198K]2 years ago

8 0

I = 0.0152 A = 15.2 mA

Explanation:

Using Ohm's law,

V = IR or

I = V/R

= (5.00 V)/(330. ohms)

= 0.0152 A

= 15.2 mA

Deffense [45]2 years ago

8 0

Answer:

From Ohms Law

V=IR

V=5volts

R=33.0hms

I=V/R

I= 5/330

=0.0152A

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Answer:

The change of the momentum of the ball is $-19.8\, \frac{mkg}{s}$

Explanation:

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It's important to note that momentum and velocity are vectors and direction matters, so if +x direction is the direction towards the wall and the -x direction away the wall $\overrightarrow{v_{i}}=+2.2\, \frac{m}{s}$ and $\overrightarrow{v_{f}}=-2.2\, \frac{m}{s}$ so (2) becomes:

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3 years ago

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Answer:

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<h3>Percentage error</h3>

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Learn more about error in measurement here: brainly.com/question/26668346

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