Answer:
a) when we approach sphere B with a positive car Q, it attracts negative charges from sphere A
b) phere A with a charge equal to zero
c) The charges are not distributed since there is no physical contact
Explanation:
a) Electric charges are neither created nor destroyed, they are only distributed, when we approach sphere B with a positive car Q, it attracts negative charges from sphere A in such a way that while the two spheres are close, each one has a charge + Q / 2.
b) when sphere B moves away, it no longer attracts negative charges from sphere A, so they move away from each other and neutralize themselves with positive charges, leaving sphere A with a charge equal to zero
c) The charges are not distributed since there is no physical contact between the two spheres, only a charge is induced when they are close, but when moving away each one is left with its initial charge
There could as smaller objects have more inertia. Mass is a measure of an objects in Harsha. Objects with greater mass have a greater in Inertia yet it’s still maintains the same amount of inertia as usual. It still has the same tendency to resist changes in its state of motion. So yes it is possible that there could ever be a situation where a small sports car would have more inertia than a big bus. :)
Answer:
0.25 m
Explanation:
Refraction occurs when the velocity or wavelength of a wave changes at the interface between two media.
We know that refractive index=
Wavelength in medium A/wavelength in medium B = velocity in medium A/velocity in medium B
Let the wavelength of medium B be a
0.5/a = 0.3/0.15
0.5 × 0.15 = 0.3 × a
a= 0.5 × 0.15/0.3
a= 0.25 m
Answer:
Option C
Explanation:
given,
velocity of airplane = 80 m/s
angle with the horizontal = 15°
speed of the ground= ?
when the plane is taking off the horizontal component of the velocity is v cosθ
so,
ground speed of the airplane is =
=
v = 77.27 m/s
horizontal velocity of the air plane comes out to be 77.27 m/s ≅ 77 m/s
so, the correct option is Option C
Answer:
The volume of the bubble near the surface will be 9.47 m³
Explanation:
Given that,
Depth = 52.0 m
Volume = 1.50 m³
Temperature at bottom = 5.5°C
Temperature at the top = 18.5°C
We need to calculate the pressure at the depth 52.0 m
The pressure is
Where, = Pressure at the surface
= Pressure at the depth
Put the value into the formula
We need to calculate the volume of the bubble just before it reaches the surface
Using equation of ideal gas
Now, The equation of at bottom and top
Put the value into the formula
Hence, The volume of the bubble near the surface will be 9.47 m³