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PilotLPTM [1.2K]
3 years ago
14

B 47° F G A C 20 J H Н

Mathematics
1 answer:
bixtya [17]3 years ago
7 0

Answer:

umm, sorry! but what are you trying to ask??

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Y=3/2(x-5) horizontal <br> Vertical
vampirchik [111]
Hello, the answer is vertical. It also shifts down 15/2 units.
3 0
3 years ago
4C2 + 6C + 3C2 - 2C - 3
Gnesinka [82]
<span><span> 4c2+6c-3c2-2c-3</span> </span>

Reformatting the input :

Changes made to your input should not affect the solution:

 (1): "c2"   was replaced by   "c^2".  1 more similar replacement(s).

Step by step solution :<span>Step  1  :
</span><span>Equation at the end of step  1  :</span><span><span> ((((4•(c2))+6c)-3c2)-2c)-3 </span><span> Step  2  :</span></span><span>Equation at the end of step  2  :</span><span> (((22c2 + 6c) - 3c2) - 2c) - 3 </span><span>Step  3  :</span>Trying to factor by splitting the middle term

<span> 3.1 </span>    Factoring <span> c2+4c-3</span> 

The first term is, <span> <span>c2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> +4c </span> its coefficient is <span> 4 </span>.
The last term, "the constant", is <span> -3 </span>

Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 1</span> • -3 = -3</span> 

Step-2 : Find two factors of  -3  whose sum equals the coefficient of the middle term, which is  <span> 4 </span>.

<span><span>     -3   +   1   =   -2</span><span>     -1   +   3   =   2
</span></span>Final result :<span> c2 + 4c - 3 </span>
3 0
3 years ago
Between which two numbers is -2/3 located on a number line
lys-0071 [83]

Answer:

It is between -2 and -3

4 0
3 years ago
Two sides of a trapezoidal are 25 meters. The third side is 40 meters. The fourth side is 20 meters shorter than the longest sid
Aloiza [94]

Answer:

110

Step-by-step explanation:

longest side would by 40 so 40 - 20 = 20. Add all the sides up 25+25+40+20=110

3 0
3 years ago
Give a geometric description of the following system of equations.a. 2x−4y=12 −3x+6y=−15.b. 2x−4y=12 −5x+3y=10.a. 2x−4y=12 −3x+6
Reptile [31]

Answer:

a. No solution, parallel lines.

b. One solution.

Step-by-step explanation:

Given the system of equations:

a. 2x-4y=12

-3x+6y=-15

b. 2x-4y=12

-5x+3y=10

To give a geometric description of the given system of equations.

The geometric description of a system of equations in 2 variables mean the system of equations will represent the number of lines equal to the number of equations in the system given.

i.e.

Number of planes = Number of variables

Number of lines = Number of equations in the system.

Here, we are given 2 variables and 2 equation in each system.

So, they can be represented in the xy-coordinates plane.

And the number of solutions to the system depends on the following condition.

Let the system of equations be:

A_1x+B_1y+C_1=0\\A_2x+B_2y+C_2=0

1. One solution:

There will be one solution to the system of equations,  If we have:

\dfrac{A_1}{A_2}\neq\dfrac{B_1}{B_2}

2. Infinitely Many Solutions: (Identical lines in the system)

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}= \dfrac{C_1}{C_2}

3. No Solution:(Parallel lines)

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}\neq\dfrac{C_1}{C_2}

Now, let us discuss the system of equations one by one:

a. 2x-4y=12 OR 2x-4y-12=0

-3x+6y=-15 OR -3x+6y+15=0

A_1 = 2, B_1 = -4, C_1 = -12\\A_2 = -3, B_2 = 6, C_2= 15

Here, the ratio:

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2} = -\dfrac{2}{3}\\\dfrac{C_1}{C_2} = -\dfrac{4}{5}

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}\neq\dfrac{C_1}{C_2}

Therefore, no solution i.e. parallel lines.

b. 2x-4y=12 OR 2x-4y-12=0

-5x+3y=10 OR -5x+3y-10=0

A_1 = 2, B_1 = -4, C_1 = -12\\A_2 = -5, B_2 = 3, C_2 = -10

\dfrac{A_1}{A_2}= -\dfrac{2}{5}\\\dfrac{B_1}{B_2} = -\dfrac{4}{3}\\\dfrac{C_1}{C_2} = -\dfrac{6}{5}

\dfrac{A_1}{A_2}\neq\dfrac{B_1}{B_2}

So, one solution.

Kindly refer to the images attached for the graphical representation of the given system of equations.

6 0
3 years ago
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