Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
Answer:
12/5
Step-by-step explanation:
tan A = opp/adj
For angle theta, 12 is the opposite leg.
13 is the hypotenuse.
We were not given the length of the adjacent leg, but we can use the Pythagorean theorem to find it.
a^2 + b^2 = c^2
a^2 + 12^2 = 13^2
a^2 + 144 = 169
a^2 = 25
a = 25
The adjacent leg has a length of 5.
tan theta = opp/adj
tan theta = 12/5
Answer: 12/5
Answer:
189
Step-by-step explanation:
each of the triangles has a area of 35 cm, so 35x4=140, then the square is 49 cm so its 140+49=189.
I believe B or C but that’s a straight guess. i would say B just because if you live like outside of town then ur screwed
Answer:
yes it is.
Step-by-step explanation:
