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VikaD [51]
3 years ago
13

How many grams of Cl are in 345 g of CaCl2

Chemistry
1 answer:
swat323 years ago
3 0
Hope this helps you.

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What kind of matter is smoke?
Neporo4naja [7]

Answer : Colloid

Explanation : Any colloid which consist of a solid evenly dispersed in a gas phase can be called as smoke. So, if smoke has to be given a matter of substance then it is can be categorized as a Colloid present in gaseous phase. Smoke is a solid which contains minute particles of dust which is homogeneously dispersed in the air.

5 0
3 years ago
Read 2 more answers
What will be the volume occupied by 2.5 moles of nitrogen gas exerting 1.75 atm of pressure at 475K?
Marina86 [1]

Answer:

THE VOLUME OF THE NITROGEN GAS AT 2.5  MOLES , 1.75 ATM AND 475 K IS 55.64 L

Explanation:

Using the ideal gas equation

PV = nRT

P = 1.75 atm

n = 2.5 moles

T = 475 K

R = 0.082 L atm/mol K

V = unknown

Substituting the variables into the equation we have:

V = nRT / P

V = 2.5 * 0.082 * 475 / 1.75

V = 97.375 / 1.75

V = 55.64 L

The volume of the 2.5 moles of nitrogen gas exerted by 1.75 atm at 475 K is 55.64 L

6 0
3 years ago
Determine the number of centiliters in 2.4 x 10^3 milliliters.
AnnZ [28]
2.4(10^3)

=2.4*10^3

=2.4*(10*10*10)

=2400 <span>milliliters

To </span>centiliters is<span> 2400mL= <u>240.0000cl. </u> </span>



8 0
3 years ago
For the reaction: 3 H2(g) + N2(g) &lt;--&gt; 2 NH3(g), the concentrations at equilbrium were [H2] = 0.10 M, [N2] = 0.10 M, and [
masya89 [10]

The equilibrium constant, k of the reaction in which case, the concentrations of the given reactants and products are as indicated is; Choice A; K = 3.1 x 10⁵

<h3>What is the equilibrium constant , k of the reaction as described in the task content?</h3>

It follows from above that the concentrations of the reactants and products are as follows; [H2] = 0.10 M, [N2] = 0.10 M, and [NH3] = 5.6 M at equilibrium.

Hence, the equilibrium constant of the reaction in discuss is;

K = [5.6]²/[0.10]³[0.10]

k = 5.6² × 10⁴

k = 3.136 × 10⁵

K = 3.1 × 10⁵.

Read more on equilibrium constant;

brainly.com/question/1619133

#SPJ1

5 0
2 years ago
Density of a piece of wood that has a measurement of 24 cm3 and 768 g
Brut [27]

Answer:

<h3>The answer is 32 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 768 g

volume = 24 cm³

We have

density =  \frac{768}{24}  \\

We have the final answer as

<h3>32 g/cm³</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
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