Answer:
22 2/9
Step-by-step explanation:
When z "varies jointly" with x and y, it can be described by the formula
z = kxy
Here, we have bags of mulch (n) varying jointly with area (a) and depth (d), both in feet. The given information can let us find the value of k.
n = kad
10 = k·(120)(1/4)
10/30 = k = 1/3 . . . . . divide by the coefficient of k
Now, we can fill in the other values of interest.
n = (1/3)·(200)·(1/3) = 200/9
n = 22 2/9
You need 22 2/9 bags of mulch to cover 200 ft² to a depth of 4 inches.
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<em>Comment on the problem</em>
This problem requires the formula be written with both area and depth expressed in feet, yet it gives depth in inches. The formula can also be written using depth in inches. In that case, k = 1/36.
Answer:
3.3
Step-by-step explanation:
Hour : H
subtract the 75 from both sidesso the variable would be on one side and the knowns would be on the other side
45H + 75 = 225
-75 -75
Divide by 45 from both sides
45H = 150
÷45 ÷45
3.33
Answer:
The equation is:
f (t) = 4 + 5 (1 - cos (2pi t / 2))
Step-by-step explanation:
with the previous exercise we look for the equation for h = f (t)
So the data we have are
Wheel diameter = 10m (wheel radius = 5m)
1 wheel gets 1 revolution in 2 minutes.
the beginning of a entry will be related to that f (0) = 4
our wish is that f (z) get at least 4 with an amplitude of 5 (this value determines the radius of the wheel) for 2 minutes
with this the particle f (t) is transformed into
f (t) = 4 + 5 (1 - cos (2pi t / 2))
We know that the maximum value of cos in t will be 0, 1 -cos has minutes, the result will be as follows:
f (t) = 4 + 5 (1 - cos (2pi t / 2))
he would be born june 12 1962
Answer:
Length = 5p + 3
Perimeter = 26p + 6
Step-by-step explanation:
Given
Area = 40p² + 24p
Width = 8p
Solving for the length of deck
Given that the deck is rectangular in shape.
The area will be calculated as thus;
Area = Length * Width
Substitute 40p² + 24p and 8p for Area and Width respectively
The formula becomes
40p² + 24p = Length * 8p
Factorize both sides
p(40p + 24) = Length * 8 * p
Divide both sides by P
40p + 24 = Length * 8
Factorize both sides, again
8(5p + 3) = Length * 8
Multiply both sides by ⅛
⅛ * 8(5p + 3) = Length * 8 * ⅛
5p + 3 = Length
Length = 5p + 3
Solving for the perimeter of the deck
The perimeter of the deck is calculated as thus
Perimeter = 2(Length + Width)
Substitute 5p + 3 and 8p for Length and Width, respectively.
Perimeter = 2(5p + 3 + 8p)
Perimeter = 2(5p + 8p + 3)
Perimeter = 2(13p + 3)
Open bracket
Perimeter = 2 * 13p + 2 * 3
Perimeter = 26p + 6
