Answer:
Towards the west
Explanation:
Magnetic force is the interaction between a moving charged particle and a magnetic field.
Magnetic force is given as
F = q (V × B)
Where F is the magnetic force
q is the charge
V is the velocity
B is the magnetic field
V×B means the cross product of the velocity and the magnetic field
NOTE:
i×i=j×j×k×k=0
i×j=k. j×i=-k
j×k=i. k×j=-i
k×i=j. i×k=-j
So, if the electron is moving southward, then, it implies that the velocity of it motion is southward, so the electron is in the positive z-direction
Also, the electron is curved upward due to the magnetic field, this implies that the force field is directed up in the positive y direction.
Then,
V = V•k
F = F•j
Then, apply the theorem
F •j = q ( V•k × B•x)
Let x be the unknown
From vector k×i =j.
This shows that x = i
Then, the magnetic field point in the direction of positive x axis, which is towards the west
You can as well use the Fleming right hand rule
The thumb represent force
The index finger represent velocity
The middle finger represent field
Answer:
The propulsion force at the moment of departure, is 49 N
Explanation:
Given;
diameter of tubes = 5 cm = 0.05 m
volumetric flow rate, V = 50 L/s = 0.005 m³/s
density of water, ρ = 1000 Kg /m³
hydraulic / propulsion force, F = ρVg
where;
ρ is the density of the fluid (water)
V is the volumetric flow rate of water
g is acceleration due to gravity
propulsion force, F = ρVg
propulsion force, F = 1000 x 0.005 x 9.8
propulsion force, F = 49 N
Therefore, the propulsion force at the moment of departure, is 49 N
Increase in height can cause climber's gravitational potential energy greater than any other mean
Hope this helps!
Answer:
The minimum thickness of the film and the wavelength of the light in air are 
and 371 nm.
Explanation:
Given that,
Refractive index of soap= 1.34
Refractive index of glass= 1.55
Wavelength = 642 nm
(I). We need to calculate the minimum thickness
Using formula of thickness
Where, m = 0 for constrictive
Put the value into the formula
(II). We need to calculate the wavelength
Using formula of wavelength
Where, m = 1
Put the value into the formula
Hence, The minimum thickness of the film and the wavelength of the light in air are and 371 nm.
Answer:
20.96 m/s
Explanation:
Using the equations of motion
y = uᵧt + gt²/2
Since the puck slides off horizontally,
uᵧ = vertical component of the initial velocity of the puck = 0 m/s
y = vertical height of the platform = 2 m
g = 9.8 m/s²
t = time of flight of the puck = ?
2 = (0)(t) + 9.8 t²/2
4.9t² = 2
t = 0.639 s
For the horizontal component of the motion
x = uₓt + gt²/2
x = horizontal distance covered by the puck
uₓ = horizontal component of the initial velocity = 20 m/s
g = 0 m/s² as there's no acceleration component in the x-direction
t = 0.639 s
x = (20 × 0.639) + (0 × 0.639²/2) = 12.78 m
For the final velocity, we'll calculate the horizontal and vertical components
vₓ² = uₓ² + 2gx
g = 0 m/s²
vₓ = uₓ = 20 m/s
Vertical component
vᵧ² = uᵧ² + 2gy
vᵧ² = 0 + 2×9.8×2
vᵧ = 6.26 m/s
vₓ = 20 m/s, vᵧ = 6.26 m/s
Magnitude of the velocity = √(20² + 6.26²) = 20.96 m/s
