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riadik2000 [5.3K]
3 years ago
13

Some major contributions to the development of atomic theory are listed. Identify the scientist associated with each contributio

n. Not all names will be used, and some names will be used more than once. He discovered the electron. He discovered periodic changes in properties of elements when they are listed in order of their atomic weights. He experimented with the deflection of cathode rays by a magnetic field. He carried out experiments that measured the scattering of alpha particles by heavy atoms. His model of the hydrogen atom led to an accurate calculation of the wavelengths of light emitted by an excited hydrogen atom. He proposed the planetary model of the atom with most of the mass of the atom concentrated in a very small nucleus. He modified the planetary model of the atom by suggesting electrons could travel about the nucleus in only a few discrete stable orbits. Answer Bank
Chemistry
1 answer:
gogolik [260]3 years ago
8 0

Answer:

He discovered the electron - J.J Thompson

He discovered periodic changes in properties of elements when they are listed in order of their atomic weights - Dimitri Mendeleev

He experimented with the deflection of cathode rays by a magnetic field - J.J Thompson

He carried out experiments that measured the scattering of alpha particles by heavy atoms - Ernest Rutherford

His model of the hydrogen atom led to an accurate calculation of the wavelengths of light emitted by an excited hydrogen atom - Neil Bohr

He proposed the planetary model of the atom with most of the mass of the atom concentrated in a very small nucleus -  Ernest Rutherford

He modified the planetary model of the atom by suggesting electrons could travel about the nucleus in only a few discrete stable orbits - Neil Bohr

Explanation:

J.J Thompson discovered the electrons. He initially called them cathode rays and he also studied how they are deflected in magnetic fields and by so doing established that they are negatively charged particles.

Ernest Rutherford is renowned for his experiment using the thin gold foil and alpha particles to determine that atoms have a positively charged massive core called the nucleus. This led to the proposition of the planetary model of the atom.

Dimitri Mendeleev discovered periodic changes in properties of elements when they are listed in order of their atomic weights. This led to the discovery of the Mendeleev  periodic table.

Neil Bohr model of the atom gave accurate explanation of the emission spectra of the hydrogen atom. His atomic model suggested that electrons could travel about the nucleus in only a few discrete stable orbits.

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Which one is the answer... a, b, or c?
jenyasd209 [6]
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the pressure and temperature of 10 liters of gas are doubled. if the original condition are 2 atmosphere of pressure and 400k wh
Harman [31]

Answer:

\boxed{\text{10 L}}

Explanation:

We have two pressures, two temperatures, and one volume.

This looks like a question in which we can use the Combined Gas Law to calculate the volume.

\dfrac{p_{1}V_{1}}{T_{1}} = \dfrac{p_{2}V_{2} }{T_{2}}

Data:

\begin{array}{rclrclrcl}p_{1}& =& \text{2 atm}\qquad & V_{1} &= & \text{10 L}\qquad & T_{2}& =& \text{400 K}\\p_{2}& =& \text{4 atm}\qquad & V_{2} &= & \text{?}\qquad & T_{2}& =& \text{800 K}\\\end{array}

Calculation:

\begin{array}{rcl}\dfrac{2 \times 10}{400}& =& \dfrac{4V_{2} }{800}\\\\0.050& = &0.0050V_{2}\\V_{2}& = &\mathbf{10 L}\end{array}\\\text{The final volume is }\boxed{\textbf{10 L}}

4 0
3 years ago
One kilogram of water at 100 0C is cooled reversibly to 15 0C. Compute the change in entropy. Specific heat of water is 4190 J/K
mina [271]

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy (s_{2} - s_{1}), in joules per gram-Kelvin, by the following model:

s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }

s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }

s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}} (1)

Where:

m - Mass, in kilograms.

c_{w} - Specific heat of water, in joules per kilogram-Kelvin.

T_{1}, T_{2} - Initial and final temperatures of water, in Kelvin.

If we know that m = 1\,kg, c_{w} = 4190\,\frac{J}{kg\cdot K}, T_{1} = 373.15\,K and T_{2} = 288.15\,K, then the change in entropy for the entire process is:

s_{2} - s_{1} = (1\,kg) \cdot \left(4190\,\frac{J}{kg\cdot K} \right)\cdot \ln \frac{288.15\,K}{373.15\,K}

s_{2} - s_{1} = -1083.112\,\frac{J}{kg\cdot K}

The change in entropy is -1083.112 joules per kilogram-Kelvin.

7 0
3 years ago
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expeople1 [14]

Answer:

An acid is a substance that donates protons (in the Brønsted-Lowry definition) or accepts a pair of valence electrons to form a bond (in the Lewis definition). A base is a substance that can accept protons or donate a pair of valence electrons to form a bond.

Hope it helps!!!

3 0
3 years ago
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