The glass composition from one manufacturer to another varies widely since glass is composed of many consitutents like sand, clay, water, a number of refractories, feldspar and many more. Hence, with the desired application, the composition must also follow. The answer in 1 is a. true. Forensic soil analysis meanwhile does require must extra experience training since it is a rigorous process. The answer 2 is b.false.
Answer:
he line begins at boron (B) and extends down to polonium (Po). Elements to the left of the line are considered metals. Elements just to the right of the line exhibit properties of both metals and nonmetals and are termed metalloids or semimetals. Elements to the far right of the periodic table are nonmetals.
Answer:
The answer is <u>applied research</u>
Explanation:
Pure research becomes <u>applied research</u> when scientists develop a hypothesis based on the data and try to solve a specific problem.
This is because the pure research try to understand, predict or explain the behavior of different phenomena <em>(the data)</em> while the applied research try to develop new technologies or methods (<em>hypothesis)</em> to take part, intervene and/or create changes on these phenomena and solve a <em>specific problem.</em>
Answer:
Explanation:
The formula for efficiency is
Data:
Useful energy = 3 J
Energy input = 30 J
Calculation:
Answer:
2.13 Kg/cm².
Explanation:
We'll begin by calculating the constant that exist between the pressure and the volume. This can be obtained by using the Boyle's law equation as shown below.
Boyle's law states that
PV = K
Where
P is the pressure.
V is the volume.
K is the constant.
We shall determine the value of K as follow:
Pressure (P) = 1.15 Kg/cm²
Volume (V) = 44.8 mL
Constant (K) =?
PV = K
1.15 × 44.8 = K
K = 51.52 Kg/cm²•mL
Finally, we shall determine pressure, when the volume is 24.2 mL. This can be obtained as follow:
Volume (V) = 24.2 mL
Constant (K) = 51.52 Kg/cm²•mL
Pressure (P) =?
PV = K
P × 24.2 = 51.52
Divide both side by 24.2
P = 51.52 / 24.2
P = 2.13 Kg/cm²
Therefore, the pressure is 2.13 Kg/cm².