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2 years ago

Which electron transition results in the emission of energy

1 answer:

3 0

Energy is emitted when an electron falls from a higher energy level to a lower one.

The transition from 3p to 3s would emit energy because the 3s sublevel is lower than the 3p.

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How many moles of aluminum oxide are produced when 6 moles of oxygen gas react?

siniylev [52]

Answer:

4 moles of aluminum and 6 moles of oxygen are produced

4 0

2 years ago

How many iron atoms are in 0.32 mol of Fe2031? 3.9x 1023 jron atoms O 3.9 iron atoms O 6.02 x 1023 iron atoms 1.9 x 1023 iron at

Gennadij [26K]

Answer: $3.9\times 10^{23}$ iron atoms

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

$1 molecule of [tex]Fe_2O_3$ contains= 2 atoms of iron

$1 mole of [tex]Fe_2O_3$ contains= $2\times 6.023\times 10^{23}=12.05\times 10^{23}$ atoms of iron

thus 0.32 moles of $Fe_2O_3$ contains= $\frac{12.05\times 10^{23}}{1}\times 0.32=3.9\times 10^{23}$ atoms of iron

Thus the sample would have $3.9\times 10^{23}$ iron atoms.

8 0

3 years ago

2. Answer the following questions about a sample of calcium phosphate:

weqwewe [10]

Answer:

a) 310.18 g/mol

b) 4.352 moles Ca3(PO4)2

c) 2.6 * 10^24 molecules

d) 5.24 * 10^24 P atoms

e)13.056 moles Ca

f)10825.3 grams

Explanation:

Step 1: Data given

Atomic mass of Ca = 40.08 g/mol

Atomic mass of P = 30.97 g/mol

Atomic mass of O = 16.0 g/mol

Step 2: Calculate molecular weight of Ca3(PO4)2

Molecular weight of Ca3(PO4)2 = 3*atomic mass of Ca + 2* atomic mass of P and 8* atomic mass of O

Molecular weight of Ca3(PO4)2 = 3*40.08 + 2*30.97 + 8*16.0 = 310.18 g/mol

Step 3: Calculate moles of Ca3(PO4)2 in 1350 grams

Moles Ca3(PO4)2 = mass Ca3(PO4)2 /molar mass

Moles Ca3(PO4)2 = 1350 grams / 310.18 g/mol

Moles Ca3(PO4)2 = 4.352 moles

Step 4: Calculate molecules in 1350 grams

Molecules = moles * number of Avogadro

Molecules = 4.352 moles * 6.02 * 10^23

Molecules = 2.6 *10^24 molecules

Step 5: Calculate moles Phosphorus

For 1 mol Ca3(PO4)2 we need 2 moles P

For 4.352 moles Ca3(PO4)2 we have 2*4.352 = 8.704 moles

Step 6: Calculate P atoms

Atoms P = 8.704 moles * 6.02*10^23

Atoms P = 5.24 * 10^24 P atoms

Step 7: Calculate moles Calcium in 1350 grams

For 1 mol Ca3(PO4)2 we have 3 moles Ca

For 4.352 moles we have 3*4.352 = 13.056 moles Ca

Step 8: Calculate mass of 2.1 * 10^25 molecules of Ca3(PO4)2

Moles Ca3(PO4)2 = 2.1 * 10^25 / 6.02 * 10^23

Moles Ca3(PO4)2 = 34.9 moles

Mass Ca3(PO4)2 = 34.9 moles * 310.18 g/mol

Mass Ca3(PO4)2 = 10825.3 grams

4 0

3 years ago

The empirical formula of a hydrocarbon (compound that contains only C and H is found to be CH. laboratory procedures have found

gulaghasi [49]

Answer:

C₆H₆

Explanation:

Molar mass of the compound is 78g/mol

Unknown:

Molecular formula of the compound = ?

Solution:

The empirical formula of the compound is CH.

Empirical formula is the simplest formula of a compound.

To solve this problem:

Find the molar mass of CH;

Molar mass = 12 + 1 = 13g/mol

Multiplication index = $\frac{78}{13}$ = 6

So;

(CH)₆ ;

Therefore:

C₆H₆

6 0

3 years ago

Whether an element is classified as a major or as a trace mineral is determined by

Aleksandr [31]

Whether an element is classified as a major or as a trace mineral is determined by "the amounts daily required by the body".

Calcium, magnesium, phosphorus, potassium, chloride and sulfur are all examples of the major minerals and these are the minerals a body needs in large quantity as opposed to include iron, copper, zinc, manganese, fluoride, selenium and cobalt, which are all trace minerals and are needed in very little quantity.

5 0

3 years ago

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