Answer:
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Answer:
Below.
Explanation:
1. Al2(SO4)^3 (aq) + 6LiOH aql) ----> 3Li2SO4 (aq) + 2Al(OH)^3 (s)
2. (NH4)2CO3 (aq) + MgCl2 (aq) ----> 2(NH4)Cl (aq) + MgCO3 (s).
Answer:
The molarity of NaOH is 0.02 M.
Explanation:
Given data:
Volume of HCl = 18.7 mL
Molarity of HCl = 0.01500 M
Volume of NaOH = 15.00 mL
Molarity of NaOH = ?
Solution:
M₁V₁ = M₂V₂
0.01500 M × 18.7 mL = M₂ × 15.00 mL
M₂ = 0.3 M.mL /15.00 mL
M₂ = 0.02 M
The molarity of NaOH is 0.02 M.
