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3 years ago

The ratio of the angles of a triangle is 3:7:2. What is the measure of the largest angle?

Mathematics

2 answers:

Karo-lina-s [1.5K]3 years ago

8 0

Answer:

the largest angle is 150°

rewona [7]3 years ago

5 0

Answer:

here's the solution,

let the given ratios as constants, by multiplying with same variable x

the angles will be 3x , 7x and 2x

now, we know the sum of the given angles measures 180°, since the sum of measures of all interior angles of a triangle is 180°

=》3x + 7x + 2x = 180°

=》12x = 180°

=》x = 15°

so, the measures of each angle is :

3x = 15 × 3 = 45°

7x = 15 × 7 = 105°

2x = 15 × 2 = 30°

and now, we can observe that the largest angle is 105°

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kirill [66]

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General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
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Step-by-step explanation:

Step 1: Define

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$\displaystyle \text{Point} \ (1, \frac{3}{2})$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y = \frac{3}{2}x^{-2}$
Basic Power Rule: $\displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}$
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Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{-3}{x^3}$

Step 3: Solve

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Divide: $\displaystyle y'(1, \frac{3}{2}) = -3$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

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3 years ago

Read 2 more answers