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Rina8888 [55]
3 years ago
12

Assume that 50,000 yd3 of the soil from a local borrow pit in Rhode Island, with a water content of 13% and dry unit weight of 8

7 pcf, is to be delivered to a construction site for some repairs of highway in I-95. By the time it reaches the site, the water content is 9%. It will be compacted to a minimum of 90% of the modified Proctor maximum dry density. Determine the total amount of water (in pounds), that must be added to the soil to increase the moisture content to the optimum level. Assume a Gs
Engineering
1 answer:
Inga [223]3 years ago
4 0

Answer:3000 yd3

Explanation:

so i got the 50000 divided it by 100 times that by 13 and got 4500 yd3

so now the soil is at 9 so i need to get the 4 percent back up so i yet again got 50000 yd3 and divided by 100 and times it by 9 to get 1500 yd3 to then minus my 1500 and 4500 yd3 and got 3000 yd3 i hope it is right.

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For a steel alloy it has been determined that a carburizing heat treatment of 15 h duration will raise the carbon concentration
Amiraneli [1.4K]

Answer:

135 hour

Explanation:

It is given that a carburizing heat treatment of 15 hour will raise the carbon concentration by 0.35 wt% at a point of 2 mm from the surface.

We have to find the time necessary to achieve the same concentration at a 6 mm position.

we know that \frac{x_1^2}{Dt}=constant where x is distance and t is time .As the temperature is constant so D will be also constant

So \frac{x_1^2}{t}=constant

then \frac{x_1^2}{t_1}=\frac{x_2^2}{t_2} we have given x_1=2 mm\ ,t_1=15 hour\ ,x_2=6\ mm and we have to find t_2 putting all these value in equation

\frac{2^2}{15}=\frac{6^2}{t_2}

so t_2=135\ hour

5 0
4 years ago
Select the best answer for the question.
dalvyx [7]
I think the Acid level
5 0
4 years ago
An unknown immiscible liquid seeps into the bottom of an open oil tank. Some measurements indicate that the depth of the unknown
barxatty [35]

Answer:

The specific weight of unknown liquid is found to be 15 KN/m³

Explanation:

The total pressure in tank is measured to be 65 KPa in the tank. But, the total pressure will be equal to the sum of pressures due to both oil and unknown liquid.

Total Pressure = Pressure of oil + Pressure of unknown liquid

65 KPa = (Specific Weight of oil)(depth of oil) + (Specific Weight of unknown liquid)(depth of unknown liquid)

65 KN/m² = (8.5 KN/m³)(5 m) + (Specific Weight of Unknown Liquid)(1.5 m)

(Specific Weight of Unknown Liquid)(1.5 m) = 65 KN/m² - 42.5 KN/m²

(Specific Weight of Unknown Liquid) = (22.5 KN/m²)/1.5 m

<u>Specific Weight of Unknown Liquid = 15 KN/m³</u>  

4 0
3 years ago
Which system of linear inequalities is represented by the graph? y &gt; x – 2 and y x + 1 y x + 1 y &gt; x – 2 and y &lt; x + 1
KatRina [158]

Answer:

The graph representing the linear inequalities is attached below.

Explanation:

The inequalities given are :

y>x-2   and y<x+1

For tables for values of x and y and get coordinates to plot for both equation.

In the first equation;

y>x-2

y=x-2

y-x = -2

The table will be :

x    y

-2  -4

-1    -3

0     -2

1      -1

2      0

The coordinates to plot are : (-2,-4) , (-1,-3), (0,-2), (1,-1) ,(2,0)

Use a dotted line and shade the part right hand side of the line.

Do the same for the second inequality equation and plot then shade the part satisfying the inequality.

The graph attached shows results.

5 0
4 years ago
Read 2 more answers
A rod that was originally 100-cm-long experiences a strain of 82%. What is the new length of the rod?
lisabon 2012 [21]

Answer:

The new length of the rod is 182 cm.

Explanation:

Given that a rod that was originally 100-cm-long experiences a strain of 82%, to determine what is the new length of the rod, the following calculation must be performed:

100 x 1.82 = X

182 = X

 

Therefore, the new length of the rod is 182 cm.

7 0
3 years ago
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