<h2>
Answer:</h2>

<h2>
Explanation:</h2>
First of all, we need to figure out what is the resistance in that line. In this problem, the total resistance is not given directly, but we can calculate it because we know it in terms of 0.51 Ω/km and since the distance from the power station to the city is 156km, then:

So we can calculate the power loss as:

Finally, the power loss due to resistance in the line is 96.09MW
Your body loses heat to the water faster than it loses heat to the air. Water has a higher heat capacity, so it is better at extracting heat than air is.
PART a)
Momentum is defined as product of mass and velocity
so here initial momentum is

given that
m = 0.3 kg
v = 18 m/s

towards East
Part b)
Since puck was initially at rest so here initial momentum must be ZERO
so here to find the force we can use

so here we have
time interval = 0.25 s
now from above equation


Part c)
Due to friction the puck lose its speed by 5 m/s
final speed = 18 - 5 = 13 m/s
mass = 0.3 kg
final momentum = (0.3)(13) = 3.9 kg m/s
now the impulse due to friction force is given as


Part d)
initial momentum of block will be ZERO as it is placed at rest
Initial momentum of the puck is given as

so total momentum before collision is given as

Part e)
since the system is isolated and there is no external force on it
So here momentum will remain conserved
so here we have




so final combined speed will be 2.6 m/s
Answer:
Explanation:
L 1: front radius 950 mm, rear radius 2700 mm, refractive index 1.528;
We shall use lens maker's formula , that is
1/f = (μ-1) ( 1/R₁ - 1/R₂) , μ is refractive index of the lens , R₁ and R₂ are radius of curvature of front and rear curved surface.
1/f₁ = (1.528-1)( 1/950 + 1/2700)
f₁ = 1331 mm
L2: front radius 535 mm, rear radius 500 mm, refractive index 1.550.
1/f₂ = (1.550-1)( 1/535 + 1/500)
f₂ = 470 mm
largest angular magnification possible
= f₁ /f₂
= 1331 / 470
= 2.83 ( approx )
Length between two lenses
=1331 +470
= 1801 mm
= 1.8 m Ans
Answer:
silver
Explanation:
It is because it contains a higher number of movable atoms ( free electrons)