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2 years ago

Magma is classified as basaltic and andesitic or rhyolitic based on my factor

1 answer:

vladimir2022 [97]2 years ago

5 0

Magma can be classified in two ways. when it is inside the volcano it is called magma, but when it is out of the volcano it is called lava or such as :
basalt, ashes, obsidian. magma is also called the names that have been listed because magma and lava are pretty much the same thing just magma is inside the volcano and lava is outside... hope this help you

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An open organ pipe 30 cm long and a closed organ pipe 23 cm long, both of same diameter , are each sounding its first overtone ,

cupoosta [38]

First overtone of open organ pipe is given as

$f_{1o} = \frac{v}{L_1 + 2e}$

first overtone of closed organ pipe is given as

$f_{1c} = \frac{3v}{4(L_2 + e)}$

now they are in unison so we will have

$\frac{v}{L_1 + 2e} = \frac{3v}{4(L_2 + e)}$

$\frac{1}{30 + 2e} = \frac{3}{4(23 + e)}$

$90 + 6e = 92 + 4e$

$e = 1 cm$

so end correction of both pipes is e = 1 cm

8 0

2 years ago

A block is resting on a platform that is rotating at an angular speed of 2.4 rad/s. The coefficient of static friction between t

Sloan [31]

Answer:

r = 0m is the Minimum distance from the axis at which the block can remain in place wothout skidding.

Explanation:

From a sum of forces:

$Ff = m*a$ where Ff = μ * N and $a = \frac{V^2}{r}=\omega^2*r$

N - m*g = 0 So, N = m*g. Replacing everything on the original equation:

$\mu*m*g = m*\omega^2*r$ (eq2)

Solving for r:

$r = \frac{\mu*g}{\omega^2}=1.41m$

If we analyze eq2 you can conclude that as r grows, the friction has to grow (assuming that ω is constant), so the smallest distance would be 0 and the greatest 1.41m. Beyond that distance, μ has to be greater than 0.83.

4 0

2 years ago

a gold smith claims that an ornament is made up of pure gold of density 19.32g c/m2 . A chain made from gold weighs 25.25g . the

Lina20 [59]

Answer:

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3 0

2 years ago

What is the pressure exerted by an elephant who weighs 2500N and whose feet cover an area of 7.5m2?

qaws [65]

Answer:

0.00339905404

Explanation:

kg: 0.00339905404

pascals: 333.333333

pounds: 0.0483459126

8 0

2 years ago

A 50-kg man is driving his snowmobile at a constant speed. The engine applies a force of 360 N and the coefficient of kinetic fr

S_A_V [24]

Answer:

134 kg

Explanation:

The snowmobile is moving at constant speed, so the acceleration is 0.

Sum of the forces in the x direction:

∑F = ma

F − 360 = 0

F = 360

Friction force equals the normal force times the coefficient of friction:

Nμ = 360

On level ground, the normal force equals the combined weight:

(m + 50)g μ = 360

m + 50 = 360 / (gμ)

m = -50 + 360 / (gμ)

m = -50 + 360 / (9.8 × 0.2)

m ≈ 134 kg

Round as needed.

8 0

2 years ago